Let the length and width of the rectangle be $5x$ and $3x$ respectively, where $x$ is a common factor. The area of the rectangle is given by:

$\text{Area} = \text{length} \times \text{width}$

Substituting the expressions for length and width:

$375 = 5x \times 3x$

$375 = 15x^2$

Now, solve for $x^2$:

$x^2 = \frac{375}{15} = 25$

Taking the square root of both sides:

$x = 5$

Now, find the actual length and width:

• Length $= 5x = 5 \times 5 = 25 \, \text{m}$
• Width $= 3x = 3 \times 5 = 15 \, \text{m}$

The perimeter of the rectangle is given by:

$\text{Perimeter} = 2(\text{length} + \text{width})$

$\text{Perimeter} = 2(25 + 15) = 2 \times 40 = 80 \, \text{m}$

Final Answer: The perimeter of the rectangle is 80 meters.

Would you like me to explain any part in more detail?

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Related Questions:

1. What would be the perimeter if the area was doubled while keeping the same ratio?
2. How would the dimensions change if the ratio was 4:3 with the same area?
3. What is the diagonal length of this rectangle?
4. How would the perimeter change if both length and width were increased by 20%?
5. Can you find the side length of a square with the same area?

Tip: When dealing with ratios and areas, always express dimensions in terms of a common variable to simplify calculations.