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We need to rewrite the expression \( 19 + \frac{7}{2 \times 6} + 1 \) using two pairs of brackets to get a total value of 2.

### Given Expression:

\[
19 + 7 \div 2 \times 6 + 1
\]

The goal is to place two pairs of brackets to make the expression equal 2.

Let’s try the following bracket placements:

\[
19 + \left( \frac{7}{2 \times 6} \right) + 1
\]

1. First, evaluate the inner bracket:
   \[
   \frac{7}{2 \times 6} = \frac{7}{12} \approx 0.5833
   \]
2. Now add:
   \[
   19 + 0.5833 + 1 = 20.5833
   \]
   This is clearly not equal to 2.

Now, let’s try a different arrangement:

\[
(19 + 7) \div (2 \times 6 + 1)
\]

1. Solve inside the brackets first:
   \[
   19 + 7 = 26
   \]
   \[
   2 \times 6 + 1 = 12 + 1 = 13
   \]
2. Now, divide:
   \[
   \frac{26}{13} = 2
   \]

So, the expression with two pairs of brackets that gives a total value of 2 is:

\[
(19 + 7) \div (2 \times 6 + 1)
\]

Would you like further clarification or details?

### Related Questions:
1. What is the general order of operations when dealing with arithmetic expressions?
2. How does changing the placement of parentheses affect the result of an expression?
3. Can you show how to simplify complex expressions involving both division and multiplication?
4. What is the importance of using brackets in mathematical expressions?
5. Can you solve another example of an arithmetic expression using two sets of brackets?

**Tip:** When dealing with multiple operations, always follow the order of operations: Parentheses, Exponents, Multiplication and Division (left to right), Addition and Subtraction (left to right).

Re-write the statement 19 + 7 ÷ 2 × 6 + 1 by including two pairs of brackets to make the total value equal to 2.

Learn how to place two pairs of brackets in the arithmetic expression 19 + 7 ÷ 2 × 6 + 1 to make the total value equal to 2. This problem teaches order of operations and bracket placement for students in Grades 7-9.

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