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The problem asks to find Raul's speed in miles per hour, given that he biked 8 miles in \( \frac{4}{5} \) of an hour.

The formula for speed is:

\[
\text{Speed} = \frac{\text{Distance}}{\text{Time}}
\]

In this case, the distance is 8 miles, and the time is \( \frac{4}{5} \) of an hour. The unit rate is found by dividing the distance by the time:

\[
\text{Speed} = \frac{8}{\frac{4}{5}} = 8 \times \frac{5}{4} = \frac{8 \times 5}{4} = \frac{40}{4} = 10 \, \text{miles per hour}.
\]

Thus, Raul's speed is **10 miles per hour**.

Would you like more details on how this was calculated or have any questions?

Here are 5 related questions to expand your understanding:
1. If Raul biked 12 miles in \( \frac{3}{4} \) hour, what would his speed be?
2. How would the speed change if the time increased to 1 hour but the distance stayed the same?
3. What is the meaning of a unit rate in the context of this problem?
4. Can the unit rate ever be a decimal, and how would you convert it from a fraction?
5. How would Raul's speed be affected if the distance were halved but the time remained the same?

**Tip:** When dividing by a fraction, multiply by its reciprocal to simplify the calculation.

Raul biked at a steady speed during his 8-mile ride. He finished the ride in 4/5 hour. What is Raul’s speed in miles per hour?

Calculate Raul's speed in miles per hour from his 8-mile bike ride completed in 4/5 hour. This lesson explains how to find the unit rate by dividing the distance by the time, suitable for Grade 6-7 students.

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