Math Problem Statement

Consider the function f(x) = 1 / (x - 3)^2. (a) Plot the graph of the function. (b) Write down the domain and range of the function. (c) Re-write the function with argument z. (d) Use your graph to estimate f(1). (e) Use the function to calculate f(1) exactly. (f) Write down another function where x = 4 has to be omitted from the domain.

Solution

(b) Domain and Range of the Function

  • Domain: The function f(x)f(x) is defined for all values of xx except where the denominator is zero. Thus, the domain is xR{3}x \in \mathbb{R} \setminus \{3\} (all real numbers except x=3x = 3).
  • Range: Since f(x)f(x) is always positive (being the reciprocal of a squared term), the range is f(x)>0f(x) > 0. Therefore, the range is (0,)(0, \infty).

(c) Re-write the Function with Argument zz

If we replace xx with zz, the function becomes: f(z)=1(z3)2f(z) = \frac{1}{(z - 3)^2}

(d) Use the Graph to Estimate f(1)f(1)

From the graph, we can observe that at x=1x = 1, the value of f(x)f(x) appears to be around 0.250.25.

(e) Calculate f(1)f(1) Exactly

To find f(1)f(1) exactly: f(1)=1(13)2=1(2)2=14f(1) = \frac{1}{(1 - 3)^2} = \frac{1}{(-2)^2} = \frac{1}{4}

(f) Modify the Function to Exclude x=4x = 4 from the Domain

To omit x=4x = 4 from the domain, we can define the function as:

\frac{1}{(x - 3)^2}, & x \neq 3 \text{ and } x \neq 4 \\ \text{undefined}, & x = 3 \text{ or } x = 4 \end{cases}$$ Would you like further details on any part? Here are five questions related to this topic for further exploration: 1. What would happen to the graph if the function was $$f(x) = \frac{1}{(x - 3)^3}$$? 2. How does shifting the function $$f(x) = \frac{1}{(x - 3)^2}$$ vertically affect the graph and range? 3. What is the significance of the vertical asymptote in this function's behavior? 4. How would you determine the horizontal asymptote of a rational function in general? 5. Can a rational function have more than one vertical asymptote? Why or why not? **Tip**: When dealing with rational functions, always identify the points where the denominator becomes zero to find the vertical asymptotes and undefined points.

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Math Problem Analysis

Mathematical Concepts

Rational Functions
Graphing Functions
Asymptotes
Domains and Ranges

Formulas

f(x) = 1 / (x - 3)^2
Domain: x ∈ ℝ, x ≠ 3
Range: f(x) > 0

Theorems

Vertical Asymptotes occur where the denominator of a rational function is zero

Suitable Grade Level

Grades 10-12