Math Problem Statement

Find f(2/3) and f(-3) for the function f(x) = (150 - 20x) / x.

Solution

The given problem provides a function f(x)=15020xxf(x) = \frac{150 - 20x}{x} and asks to find f(23)f\left(\frac{2}{3}\right) and f(3)f(-3).

Let's calculate these values step-by-step.

1. Calculate f(23)f\left(\frac{2}{3}\right):

f(23)=15020(23)23f\left(\frac{2}{3}\right) = \frac{150 - 20\left(\frac{2}{3}\right)}{\frac{2}{3}} Simplify the numerator: 15020(23)=150403=4503403=4103150 - 20\left(\frac{2}{3}\right) = 150 - \frac{40}{3} = \frac{450}{3} - \frac{40}{3} = \frac{410}{3}

Now divide by 23\frac{2}{3}: f(23)=410323=4103×32=4102=205f\left(\frac{2}{3}\right) = \frac{\frac{410}{3}}{\frac{2}{3}} = \frac{410}{3} \times \frac{3}{2} = \frac{410}{2} = 205

So, f(23)=205f\left(\frac{2}{3}\right) = 205.

2. Calculate f(3)f(-3):

f(3)=15020(3)3f(-3) = \frac{150 - 20(-3)}{-3} Simplify the numerator: 15020(3)=150+60=210150 - 20(-3) = 150 + 60 = 210

Now divide by 3-3: f(3)=2103=70f(-3) = \frac{210}{-3} = -70

So, f(3)=70f(-3) = -70.

Final Answers:

  1. f(23)=205f\left(\frac{2}{3}\right) = 205
  2. f(3)=70f(-3) = -70

Would you like more details on any of the steps or have additional questions?

Related Questions:

  1. How do you simplify complex fractions step-by-step?
  2. What are the properties of rational functions?
  3. How do you find vertical and horizontal asymptotes of a function like f(x)f(x)?
  4. What is the domain and range of the function f(x)=15020xxf(x) = \frac{150 - 20x}{x}?
  5. How do you determine critical points for f(x)f(x)?

Tip: Always check the domain of a function before calculating specific values, especially for rational functions where the denominator can be zero.

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Math Problem Analysis

Mathematical Concepts

Algebra
Rational Functions
Substitution

Formulas

f(x) = (150 - 20x) / x

Theorems

Rational Function Evaluation

Suitable Grade Level

Grades 9-11