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We are given the graph of a rational function \( f(x) \) with several key characteristics:

1. **Vertical asymptotes at** \( x = 1 \) and \( x = 6 \)
2. **Horizontal asymptote** at \( y = 0 \)
3. **x-intercept** at \( x = 4 \)
4. **Point (0, 2)** lies on the graph

The problem asks us to select the appropriate form for \( f(x) \) from five options, then determine the equation.

### Step-by-step reasoning:

- **Asymptotes**: The vertical asymptotes at \( x = 1 \) and \( x = 6 \) imply factors of \( (x - 1) \) and \( (x - 6) \) in the denominator.
  
- **x-intercept** at \( x = 4 \): The function has an x-intercept at 4, so the numerator must have a factor of \( (x - 4) \), since setting \( x = 4 \) should make \( f(x) = 0 \).

- **Horizontal asymptote** at \( y = 0 \): Since the horizontal asymptote is \( y = 0 \), the degree of the numerator must be less than or equal to the degree of the denominator. This implies that the form of \( f(x) \) should be of the type \(\frac{a(x - 4)}{(x - 1)(x - 6)}\).

Given these conditions, the appropriate form for \( f(x) \) appears to be:

\[
f(x) = \frac{a(x - 4)}{(x - 1)(x - 6)}
\]

### To find the constant \( a \):
We are told that the graph passes through the point \( (0, 2) \). Substituting \( x = 0 \) and \( f(0) = 2 \) into the equation:

\[
2 = \frac{a(0 - 4)}{(0 - 1)(0 - 6)}
\]

Simplifying:

\[
2 = \frac{a(-4)}{( -1)(-6)} = \frac{-4a}{6} = \frac{-2a}{3}
\]

Solving for \( a \):

\[
2 = \frac{-2a}{3} \quad \Rightarrow \quad a = -3
\]

### Final equation:
Thus, the equation for \( f(x) \) is:

\[
f(x) = \frac{-3(x - 4)}{(x - 1)(x - 6)}
\]

Would you like a more detailed explanation, or do you have any further questions?

### Related questions:
1. How do vertical and horizontal asymptotes affect the shape of rational functions?
2. Why does the factor \( (x - 4) \) in the numerator give the x-intercept at \( x = 4 \)?
3. How does the degree of the numerator compared to the denominator determine the horizontal asymptote?
4. What happens to the graph of a rational function when the sign of \( a \) changes?
5. How do you determine the constant \( a \) when given a point on the graph?

#### Tip:
For rational functions, the number and location of vertical asymptotes come from the roots of the denominator, while the horizontal asymptote is determined by the degrees of the numerator and denominator.

The figure below shows the graph of a rational function f(x). It has vertical asymptotes x = 1 and x = 6, and horizontal asymptote y = 0. The graph has x-intercept 4, and it passes through the point (0, 2). The equation for f(x) has one of the five forms shown below. Choose the appropriate form for f(x), and then write the equation.

Learn how to solve a rational function with vertical asymptotes at x = 1 and x = 6, horizontal asymptote y = 0, and x-intercept at x = 4. The function also passes through point (0, 2). This solution uses core concepts of asymptotes and rational function behavior. Suitable for Grades 10-12 students.

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