Math Problem Statement

Amanda, Brandon and Charlene shared the cost for a present. Amandas share of the cost to Brandons share of the cost was 4 : 5. Brandons share of the cost to Charlenes share of the cost was 2 : 3. Amanda and Charlene gave a total of R46 for the present. What was the cost of the present?

Solution

We are given the ratios of how Amanda, Brandon, and Charlene shared the cost of a present, and we know the total contribution of Amanda and Charlene. Let's denote their contributions as follows:

  • Let Amanda's share be AA,
  • Brandon's share be BB,
  • Charlene's share be CC.

We are given two ratios:

  1. AB=45\frac{A}{B} = \frac{4}{5}, which means Amanda's share is 4 parts for every 5 parts of Brandon's share.
  2. BC=23\frac{B}{C} = \frac{2}{3}, which means Brandon's share is 2 parts for every 3 parts of Charlene's share.

Additionally, we know that Amanda and Charlene together contributed R46: A+C=46A + C = 46

Step 1: Express shares in terms of a common variable

We first express all shares in terms of a common variable. From the ratio AB=45\frac{A}{B} = \frac{4}{5}, we can express AA and BB in terms of a variable xx: A=4x,B=5xA = 4x, \quad B = 5x

From the ratio BC=23\frac{B}{C} = \frac{2}{3}, we can express BB and CC in terms of another variable yy: B=2y,C=3yB = 2y, \quad C = 3y

Step 2: Relate the two expressions for BB

We now have two expressions for BB: one from the first ratio and another from the second ratio: 5x=2y5x = 2y Solve for yy in terms of xx: y=5x2y = \frac{5x}{2}

Step 3: Substitute yy into the equation for CC

Now substitute y=5x2y = \frac{5x}{2} into the expression for CC: C=3y=3×5x2=15x2C = 3y = 3 \times \frac{5x}{2} = \frac{15x}{2}

Step 4: Use the total contribution of Amanda and Charlene

We know that Amanda and Charlene's combined contribution is R46: A+C=46A + C = 46 Substitute A=4xA = 4x and C=15x2C = \frac{15x}{2} into this equation: 4x+15x2=464x + \frac{15x}{2} = 46 Multiply through by 2 to eliminate the fraction: 8x+15x=928x + 15x = 92 Combine like terms: 23x=9223x = 92 Solve for xx: x=9223=4x = \frac{92}{23} = 4

Step 5: Find the total cost of the present

Now that we have x=4x = 4, we can find the shares of Amanda, Brandon, and Charlene:

  • A=4x=4×4=16A = 4x = 4 \times 4 = 16,
  • B=5x=5×4=20B = 5x = 5 \times 4 = 20,
  • C=15x2=15×42=30C = \frac{15x}{2} = \frac{15 \times 4}{2} = 30.

The total cost of the present is the sum of their contributions: A+B+C=16+20+30=66A + B + C = 16 + 20 + 30 = 66

Thus, the total cost of the present is R66.

Would you like a more detailed explanation of any step, or do you have any questions?

Here are five related questions to consider:

  1. If the total contribution was R92 instead of R46, what would be the new total cost of the present?
  2. How would the problem change if Amanda and Charlene gave a total of R60 for the present?
  3. If the ratio between Amanda's and Brandon's share was 5:6, how would the calculations change?
  4. What if Charlene's contribution was doubled—how would that affect the total cost?
  5. How would the solution differ if all three contributed equally?

Tip: Always check if the sum of individual shares adds up correctly to the total cost when dealing with ratios.

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Math Problem Analysis

Mathematical Concepts

Ratios
Algebra
Linear Equations

Formulas

A/B = 4/5 (Amanda's share to Brandon's share)
B/C = 2/3 (Brandon's share to Charlene's share)
A + C = 46 (Total contribution of Amanda and Charlene)

Theorems

Ratio Proportions
Linear Equation Solving

Suitable Grade Level

Grades 8-10