Math Problem Statement

A tank of water went from 108L to 94.5L in 1.5 mins find the rate of discharge

Solution

To find the rate of discharge, we need to calculate how much water was discharged over the given time and then divide it by the time to get the rate.

Step 1: Find the total volume of water discharged.

Initial volume = 108 L
Final volume = 94.5 L

Discharged volume = Initial volume - Final volume
Discharged volume = 108L94.5L=13.5L108 \, \text{L} - 94.5 \, \text{L} = 13.5 \, \text{L}

Step 2: Find the rate of discharge.

The time taken is 1.5 minutes. The rate is given by the formula:

Rate of discharge=Volume dischargedTime taken\text{Rate of discharge} = \frac{\text{Volume discharged}}{\text{Time taken}}

Rate of discharge=13.5L1.5min=9L/min\text{Rate of discharge} = \frac{13.5 \, \text{L}}{1.5 \, \text{min}} = 9 \, \text{L/min}

Conclusion:

The rate of discharge is 9L/min9 \, \text{L/min}.

Would you like a more detailed explanation, or do you have any follow-up questions?

Related Questions:

  1. How would the rate of discharge change if the time increased to 3 minutes?
  2. If the tank initially held 150L of water, how much water would have been discharged after 2 minutes at the same rate?
  3. How can we calculate the remaining volume of water in the tank if the discharge continues at the same rate for 5 minutes?
  4. What is the rate of discharge in L/s\text{L/s} if the time is converted to seconds?
  5. How can the rate of discharge affect the time needed to empty the tank completely?

Tip: Always ensure the units are consistent when performing calculations (e.g., time in minutes and volume in liters).

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Math Problem Analysis

Mathematical Concepts

Rate of Discharge
Volume
Time

Formulas

Rate of discharge = Volume discharged / Time taken

Theorems

Concept of rate of change

Suitable Grade Level

Grades 7-9