Math Problem Statement
Range of the function f(x)=tan-1(√[x]+[-x])+√2-|x| +1/x² is
Solution
We are tasked with finding the range of the function:
Let's break it down step by step:
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Inverse tangent (arctan): has a range of for all real values of .
-
Analysis of : The square root function, , is defined for . Therefore, this function is undefined for negative values of , limiting the domain of to .
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Behavior of for non-negative :
- For , (since the greatest integer less than or equal to is 0). So the expression simplifies to just .
The range of as varies from to is .
-
Additional terms:
- is constant and equals approximately 1.414.
- for is just , so the term becomes .
- The term is always positive for and tends to 0 as , but becomes very large as .
Considerations for the range:
- The term is bounded by .
- shifts the overall function upward by 1.414.
- The term decreases as increases.
- increases rapidly as approaches 0, adding a very large positive value near .
Behavior at the boundaries:
-
As :
- ,
- ,
- ,
- .
Therefore, as approaches 0, .
-
As :
- ,
- ,
- ,
- .
So, as grows large, .
Conclusion:
The function tends to as and as . Hence, the range of the function is:
Do you need further details or explanations on any step?
Here are five related questions:
- What is the range of ?
- How do you find the domain of a function involving square roots?
- What is the range of the function ?
- What properties does the function have?
- What are the critical points of ?
Tip: When working with inverse trigonometric functions, it’s useful to remember their principal value ranges!
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Math Problem Analysis
Mathematical Concepts
Inverse Trigonometric Functions
Square Roots
Absolute Value
Asymptotic Behavior
Formulas
f(x) = tan^(-1)(√x + [-x]) + √2 - |x| + 1/x²
Range of tan^(-1)(y): (-π/2, π/2)
Square root function: √x
Absolute value function: |x|
Theorems
Range of inverse tangent function
Behavior of rational functions as x → 0 and x → ∞
Suitable Grade Level
Grade 11-12 and beyond (advanced high school or early college level)
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