Math Problem Statement
what's the radius and interval of convergence of the series ((-1)^n(x-2)^n)/(n2^n)
Solution
To determine the radius and interval of convergence of the series
we will use the Ratio Test to find the radius of convergence, and then identify the interval.
Step 1: Apply the Ratio Test
The Ratio Test is used to find the radius of convergence for power series. The general form of the Ratio Test is:
For the given series, the general term is:
Now, apply the Ratio Test:
Simplifying:
Now, take the limit as :
For the series to converge, we require this limit to be less than 1:
Step 2: Solve for the Radius of Convergence
Solve the inequality:
Multiplying both sides by 2:
This gives the radius of convergence , and the series converges for in the interval:
Step 3: Check the Endpoints
We need to check whether the series converges at the endpoints and .
- At : The series becomes:
This is the harmonic series, which diverges.
- At : The series becomes:
This is the alternating harmonic series, which converges.
Conclusion:
- Radius of Convergence:
- Interval of Convergence: , or
Would you like further details on any of the steps? Here are some related questions:
- How does the Ratio Test work in determining the radius of convergence?
- What happens if we apply the Root Test instead of the Ratio Test?
- Why does the alternating harmonic series converge, and what tests can confirm this?
- How can we graphically represent the convergence of power series?
- What is the difference between conditional and absolute convergence?
Tip: Always check the behavior at the endpoints of the interval when using the Ratio Test to determine convergence!
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Math Problem Analysis
Mathematical Concepts
Power Series
Convergence
Ratio Test
Harmonic Series
Alternating Series
Formulas
Ratio Test: L = lim(n -> ∞) |a_(n+1)/a_n|
|(x - 2) / 2| < 1
Theorems
Ratio Test
Harmonic Series Convergence
Alternating Series Test
Suitable Grade Level
College/Advanced High School (Grades 11-12, Undergraduate)
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