Math Problem Statement

Answer the following questions related to modulus operation and division: Find the quotient and remainder for the given problems involving numbers like 25 ÷ 6, 27 ÷ 9, and more. Also, find the modulus for larger numbers like 618432955 mod 101 and 345828498 mod 101.

Solution

Let's solve the given problems based on the modulus operation explanation in your image.

We are asked to calculate the quotient and the remainder (modulus) for several division problems. Here's the breakdown:

Example Formula:

For any integers aa and bb, we have: a=bq+rwhere0r<ba = bq + r \quad \text{where} \quad 0 \leq r < b This means the remainder rr, when dividing aa by bb, must be non-negative and less than bb.


Solving the Given Problems:

  1. The quotient of 25÷625 \div 6:

    • 25=6×4+125 = 6 \times 4 + 1
    • Quotient = 4, 25mod6=125 \mod 6 = 1
  2. The quotient of 27÷927 \div 9:

    • 27=9×3+027 = 9 \times 3 + 0
    • Quotient = 3, 27mod9=027 \mod 9 = 0
  3. The quotient of 22÷1022 \div 10:

    • 22=10×2+222 = 10 \times 2 + 2
    • Quotient = 2, 22mod10=222 \mod 10 = 2
  4. The quotient of 21÷1021 \div 10:

    • 21=10×2+121 = 10 \times 2 + 1
    • Quotient = 2, 21mod10=121 \mod 10 = 1
  5. The quotient of 22÷722 \div 7:

    • 22=7×3+122 = 7 \times 3 + 1
    • Quotient = 3, 22mod7=122 \mod 7 = 1
  6. The quotient of 27÷827 \div 8:

    • 27=8×3+327 = 8 \times 3 + 3
    • Quotient = 3, 27mod8=327 \mod 8 = 3

Now, for the larger numbers:

  1. 618432955mod101618432955 \mod 101:

    • Quotient: 618432955÷1016122148618432955 \div 101 \approx 6122148
    • Remainder: 618432955(6122148×101)=27618432955 - (6122148 \times 101) = 27
    • 618432955mod101=27618432955 \mod 101 = 27
  2. 345828498mod101345828498 \mod 101:

    • Quotient: 345828498÷1013424044345828498 \div 101 \approx 3424044
    • Remainder: 345828498(3424044×101)=54345828498 - (3424044 \times 101) = 54
    • 345828498mod101=54345828498 \mod 101 = 54

Let me know if you'd like further details or explanations on any of these! Here are five follow-up questions:

  1. How do you determine the remainder in modulus operations?
  2. What is the significance of the non-negative remainder in the modulus operation?
  3. Can you find the modulus of 100÷7100 \div 7?
  4. Why does amodba \mod b always produce a result in the range 0r<b0 \leq r < b?
  5. How does the division algorithm help in finding the modulus?

Tip: Always remember to first find the quotient, and then compute the remainder using r=abqr = a - bq.

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Math Problem Analysis

Mathematical Concepts

Division
Modulus
Remainders

Formulas

a = bq + r, where 0 ≤ r < b

Theorems

Division Algorithm

Suitable Grade Level

Grades 6-8