Math Problem Statement

given f(x)=√x and g(x)=√4-x^2 find (f/g)(x) then find the domain of f/g

Solution

We are given the functions f(x)=xf(x) = \sqrt{x} and g(x)=4x2g(x) = \sqrt{4 - x^2}, and we need to find (fg)(x)\left(\frac{f}{g}\right)(x), as well as the domain of (fg)(x)\left(\frac{f}{g}\right)(x).

Step 1: Finding (fg)(x)\left(\frac{f}{g}\right)(x)

The quotient of f(x)f(x) and g(x)g(x) is given by:

(fg)(x)=f(x)g(x)=x4x2.\left(\frac{f}{g}\right)(x) = \frac{f(x)}{g(x)} = \frac{\sqrt{x}}{\sqrt{4 - x^2}}.

Step 2: Finding the domain of (fg)(x)\left(\frac{f}{g}\right)(x)

The domain of (fg)(x)\left(\frac{f}{g}\right)(x) consists of values of xx for which both f(x)f(x) and g(x)g(x) are defined, and g(x)0g(x) \neq 0.

Domain of f(x)=xf(x) = \sqrt{x}

The square root function is defined when the argument is non-negative, meaning: x0.x \geq 0. So, the domain of f(x)f(x) is [0,)[0, \infty).

Domain of g(x)=4x2g(x) = \sqrt{4 - x^2}

Similarly, for g(x)g(x) to be defined, the argument inside the square root must be non-negative: 4x20.4 - x^2 \geq 0. This simplifies to: x24,x^2 \leq 4, which gives: 2x2.-2 \leq x \leq 2. Thus, the domain of g(x)g(x) is [2,2][-2, 2].

Combining the Domains

To find the domain of (fg)(x)\left(\frac{f}{g}\right)(x), we need the intersection of the domains of f(x)f(x) and g(x)g(x), and also ensure that g(x)0g(x) \neq 0.

  • The domain of f(x)f(x) is [0,)[0, \infty).
  • The domain of g(x)g(x) is [2,2][-2, 2].

The intersection of these two domains is [0,2][0, 2], meaning x[0,2]x \in [0, 2].

Ensuring g(x)0g(x) \neq 0

We also need to exclude any values where g(x)=0g(x) = 0. The function g(x)=4x2g(x) = \sqrt{4 - x^2} equals 0 when: 4x2=0orx=2.4 - x^2 = 0 \quad \text{or} \quad x = 2. Thus, g(2)=0g(2) = 0, and we must exclude x=2x = 2 from the domain.

Final Domain

The domain of (fg)(x)\left(\frac{f}{g}\right)(x) is [0,2)[0, 2).

Conclusion

(fg)(x)=x4x2\left(\frac{f}{g}\right)(x) = \frac{\sqrt{x}}{\sqrt{4 - x^2}} with domain x[0,2)x \in [0, 2).

Do you need more details or have any questions?

Here are 5 related questions:

  1. What is the domain of f(x)=1xf(x) = \frac{1}{\sqrt{x}}?
  2. How would the domain change if g(x)=9x2g(x) = \sqrt{9 - x^2} instead?
  3. Can you find the range of f(x)f(x) and g(x)g(x)?
  4. What happens to the domain if we add a constant inside the square roots?
  5. How do you find the domain of a general rational function?

Tip: Always check if the denominator of a fraction is zero to avoid undefined values when finding domains.

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Math Problem Analysis

Mathematical Concepts

Functions
Square Roots
Domain of Functions
Rational Functions

Formulas

(f/g)(x) = √x / √(4 - x^2)
Domain of f(x): x ≥ 0
Domain of g(x): -2 ≤ x ≤ 2

Theorems

Domain of a square root function
Intersection of domains
Exclusion of zero from the denominator

Suitable Grade Level

Grades 10-12