Math Problem Statement
Solution
Let's solve the problem step by step using the data provided.
The dataset is:
Part a: Finding the quartiles
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Step 1: Arrange the data in ascending order:
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Step 2: Find the quartiles.
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First quartile (Q1): This is the median of the lower half of the data (excluding the median of the full set). For the ordered list, the lower half is: The median of this subset is 58, so .
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Second quartile (Q2): This is the median of the entire dataset. Since there are 15 values, the median is the 8th value in the ordered list, which is 59. So .
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Third quartile (Q3): This is the median of the upper half of the data. The upper half is: The median of this subset is 62, so .
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Part b: Find the interquartile range (IQR)
The interquartile range is calculated as:
Part c: Identify any outliers
To find outliers, use the formula: Any data point below 52 or above 68 is considered an outlier. The only value above 68 is 75, so 75 is an outlier.
Summary:
- IQR = 4
- Outlier: 75
Would you like any further details or explanations?
Here are 5 related questions:
- How is the median different from the mean in a dataset?
- How can you visually represent quartiles using a box plot?
- What is the significance of the interquartile range in data analysis?
- How do you determine extreme outliers beyond the regular outlier threshold?
- In what types of datasets are quartiles most useful?
Tip: Quartiles and IQR are very useful in identifying skewness or outliers in your data. Always check them before calculating the mean or making assumptions about the data's distribution.
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Math Problem Analysis
Mathematical Concepts
Statistics
Quartiles
Interquartile Range
Outliers
Formulas
First quartile (Q1) = Median of lower half of data
Second quartile (Q2) = Median of entire dataset
Third quartile (Q3) = Median of upper half of data
Interquartile range (IQR) = Q3 - Q1
Outliers: Lower bound = Q1 - 1.5 * IQR, Upper bound = Q3 + 1.5 * IQR
Theorems
Median
Quartile Theorem
Suitable Grade Level
Grades 9-12
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