10L water is added to vessel containing 40L of pure milk. 25L of the resultant mixture was then sold and some more quantity of pure milk and water was added to the vessel in the ratio 2:1. If the resultant respective ratio of milk and water in the vessel was 3:1, then what was the quantity of pure milk added in the vessel?

Let's break down the problem step by step to find out the quantity of pure milk added to the vessel.

### Step 1: Initial quantities of milk and water

- Initially, the vessel contains 40 liters of **pure milk**.
- 10 liters of **water** is added to the vessel, making the total mixture 50 liters, with 40 liters of milk and 10 liters of water.

So, the ratio of milk to water in the vessel is:
\[
\text{Milk:Water} = \frac{40}{10} = 4:1
\]

### Step 2: 25 liters of the mixture is sold

Since the ratio of milk to water is 4:1, out of the 25 liters sold:
- Milk sold = \( \frac{4}{5} \times 25 = 20 \) liters
- Water sold = \( \frac{1}{5} \times 25 = 5 \) liters

### Step 3: Remaining quantities of milk and water after selling

After selling 25 liters of the mixture, the remaining quantities in the

Solve the problem where 10L of water is added to 40L of pure milk, and after selling 25L of the mixture, more pure milk and water are added in the ratio of 2:1. Find out how much pure milk was added to achieve the final 3:1 milk-to-water ratio. Detailed step-by-step solution with ratio and mixture calculations. Suitable for students in Grades 8-10.

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