https://file.aiquickdraw.com/mathbot/file/17293670659305r0ur1bk.jpg

The problem asks for the zeros of the quadratic function:

\[
x^2 - 4x - 5 = 0
\]

To find the zeros of this quadratic, we can factor the expression. We're looking for two numbers that multiply to \(-5\) and add to \(-4\).

The two numbers are \(-5\) and \(1\), so we can factor the quadratic as:

\[
(x - 5)(x + 1) = 0
\]

Now, set each factor equal to zero:

1. \(x - 5 = 0 \Rightarrow x = 5\)
2. \(x + 1 = 0 \Rightarrow x = -1\)

Thus, the zeros of the function are \(x = -1\) and \(x = 5\).

Therefore, the correct answer is:

\[
x = -1 \quad \text{and} \quad x = 5
\]

Would you like more details or explanations? Here are some related questions:

1. How can we verify the zeros of a quadratic function?
2. Can all quadratic equations be factored easily?
3. How would the quadratic formula be used to solve this problem?
4. What does it mean geometrically for a quadratic to have two real zeros?
5. How does the discriminant of a quadratic help in determining the nature of its solutions?

**Tip:** Always try factoring first for simple quadratics before using the quadratic formula.

The graph of the quadratic function x^2 - 4x - 5 = 0 crosses the x-axis at x = -1 and x = 5. What are the zeros of this function?

Learn how to find the zeros of the quadratic equation x^2 - 4x - 5 = 0 by factoring. This problem is suitable for students in grades 8-10 and covers key algebraic concepts like factoring and the zero-product property.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation