Math Problem Statement

find the quadratic polynomial the sum and product of whose zeroes are -3 and 2 respectively

Solution

The general form of a quadratic polynomial when the sum and product of its zeroes are given can be written as:

p(x)=x2(sum of zeroes)x+(product of zeroes)p(x) = x^2 - (\text{sum of zeroes})x + (\text{product of zeroes})

Here, the given sum of the zeroes is 3-3 and the product of the zeroes is 22. Substituting these values into the formula:

p(x)=x2(3)x+2p(x) = x^2 - (-3)x + 2

Simplify:

p(x)=x2+3x+2p(x) = x^2 + 3x + 2

Thus, the quadratic polynomial is:

p(x)=x2+3x+2\boxed{p(x) = x^2 + 3x + 2}


Would you like me to explain further or verify by solving for the roots?
Here are five related questions to explore:

  1. How do you verify that given roots satisfy the polynomial?
  2. Can you derive the quadratic equation if roots are given explicitly instead of their sum and product?
  3. What is the relationship between coefficients and roots in any polynomial?
  4. How do you factorize a quadratic polynomial like x2+3x+2x^2 + 3x + 2?
  5. What is the graphical interpretation of the sum and product of the roots?

Tip: The coefficient of xx in a quadratic equation is always (sum of the roots)-(\text{sum of the roots}).

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Polynomials
Roots of Quadratic Equations

Formulas

General form of a quadratic polynomial: p(x) = x^2 - (sum of roots)x + (product of roots)

Theorems

Relationship between roots and coefficients in a quadratic equation

Suitable Grade Level

Grades 8-10