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The problem asks you to write a quadratic function with zeros \( -8 \) and \( -6 \). 

A quadratic function can be expressed in factored form as:
\[
f(x) = a(x - r_1)(x - r_2)
\]
where \( r_1 \) and \( r_2 \) are the zeros of the function. In this case, \( r_1 = -8 \) and \( r_2 = -6 \), and the leading coefficient \( a \) is given as 1.

So, the factored form of the quadratic is:
\[
f(x) = (x + 8)(x + 6)
\]

Now, expand the expression to get it in standard form:
\[
f(x) = (x + 8)(x + 6) = x^2 + 6x + 8x + 48 = x^2 + 14x + 48
\]

Thus, the quadratic function is:
\[
f(x) = x^2 + 14x + 48
\]

Would you like more details or have any questions?

Here are 5 related questions to explore:
1. How do you find the zeros of a quadratic function?
2. What is the factored form of a quadratic equation?
3. Can a quadratic function have complex zeros?
4. How do you determine the vertex of a quadratic function?
5. What is the axis of symmetry of a quadratic function?

**Tip:** Always check the expanded form after factoring to ensure correctness.

Write a quadratic function with zeros -8 and -6. Write your answer using the variable x and in standard form with a leading coefficient of 1.

Discover how to write a quadratic function with zeros -8 and -6 in standard form. This problem explores key algebraic concepts, including factoring and the Zero Product Property. Suitable for students in Grades 9-11.

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