Math Problem Statement

y=x^2-6x+9

Solution

The equation you provided is a quadratic function:

y=x26x+9y = x^2 - 6x + 9

Factored Form:

We can factor the quadratic expression to find the roots (or solutions) of the equation.

y=(x3)2y = (x - 3)^2

This shows that the quadratic can be written as a perfect square trinomial.

Vertex Form:

Since the equation is in the form (xh)2+k(x - h)^2 + k, where (h,k)(h, k) is the vertex, we can identify:

  • Vertex: (3,0)(3, 0)

Axis of Symmetry:

The axis of symmetry for the parabola is the vertical line that passes through the vertex:

x=3x = 3

Direction of the Parabola:

The parabola opens upward because the coefficient of x2x^2 is positive.

Key Points:

  • Vertex: (3,0)(3, 0)
  • Y-intercept: Set x=0x = 0 to find the y-intercept: y=026(0)+9=9y = 0^2 - 6(0) + 9 = 9
  • X-intercept: Since the vertex is on the x-axis, the x-intercept is the same as the vertex: (3,0)(3, 0)

Would you like more details or have any questions? Here are some related questions:

  1. How do you complete the square to convert a quadratic equation to vertex form?
  2. What is the significance of the discriminant in a quadratic equation?
  3. How do you graph a quadratic function given its equation?
  4. Can you explain how to find the focus and directrix of a parabola?
  5. What are the applications of quadratic functions in real life?

Tip: Always check for factoring opportunities when solving quadratic equations, as it simplifies finding the roots and understanding the graph.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Functions
Factoring
Vertex Form

Formulas

Quadratic expression y = ax^2 + bx + c
Vertex form (x - h)^2 + k

Theorems

Factoring quadratic expressions
Vertex form of a quadratic equation

Suitable Grade Level

Grades 8-10