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The graph you provided shows a parabola opening downwards. This suggests that the quadratic function that describes this graph is of the form \( y = ax^2 + bx + c \), where \( a < 0 \) because the parabola is facing downward.

### To find the range:
1. **Identify the vertex:** 
   The vertex of a downward-opening parabola represents the maximum point, which determines the upper bound of the range.
   
   From the graph, the vertex appears to be at \( (0, 3) \), meaning the maximum value of \( y \) is 3.

2. **Determine the range:**
   Since the parabola opens downwards, the range includes all values of \( y \) from negative infinity up to the maximum value of \( 3 \).

Thus, the range of the function is:
\[
y \in (-\infty, 3]
\]

Would you like more details or have any other questions?

Here are five related questions to consider:
1. What is the domain of this quadratic function?
2. How do you find the vertex algebraically for a general quadratic function?
3. What is the significance of the axis of symmetry in a parabola?
4. How can you determine the direction a parabola opens from its equation?
5. What is the vertex form of a quadratic function?

**Tip:** In quadratic functions, the coefficient \( a \) controls the direction and width of the parabola—when \( a > 0 \), the parabola opens upwards; when \( a < 0 \), it opens downwards.

Discover how to determine the range of a quadratic function from a graph of a downward-opening parabola. The vertex represents the maximum point, and the range includes all values of y from negative infinity to the vertex's y-coordinate.

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