The graph you provided shows a parabola opening downwards. This suggests that the quadratic function that describes this graph is of the form $y = ax^2 + bx + c$, where $a < 0$ because the parabola is facing downward.

To find the range:

1. Identify the vertex: The vertex of a downward-opening parabola represents the maximum point, which determines the upper bound of the range.

   From the graph, the vertex appears to be at $(0, 3)$, meaning the maximum value of $y$ is 3.

2. Determine the range: Since the parabola opens downwards, the range includes all values of $y$ from negative infinity up to the maximum value of $3$.

Thus, the range of the function is: $y \in (-\infty, 3]$

Would you like more details or have any other questions?

Here are five related questions to consider:

1. What is the domain of this quadratic function?
2. How do you find the vertex algebraically for a general quadratic function?
3. What is the significance of the axis of symmetry in a parabola?
4. How can you determine the direction a parabola opens from its equation?
5. What is the vertex form of a quadratic function?

Tip: In quadratic functions, the coefficient $a$ controls the direction and width of the parabola—when $a > 0$, the parabola opens upwards; when $a < 0$, it opens downwards.