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Can you solve this problem using this formula L x W and use factoring

Let's solve this problem step by step, using the given formula \( L \times W \) (Length times Width), and apply factoring.

### Problem Restatement:

We are told:
- The length of a rectangular backyard is 9 meters more than its width.
- The area of the backyard is 136 square meters.

Let:
- \( W \) be the width of the backyard.
- \( L \) be the length of the backyard.

From the information, we know that:
- \( L = W + 9 \) (since the length is 9 meters more than the width).
- The area \( A \) is given by the formula \( L \times W = 136 \).

### Step 1: Set up the equation using the area formula
Substitute \( L = W + 9 \) into the area formula:

\[
(W + 9) \times W = 136
\]

### Step 2: Expand the equation
Expand the left-hand side:

\[
W^2 + 9W = 136
\]

### Step 3: Rearrange into standard quadratic form
Move all terms to one side to set the equation to 0:

\[
W^2 + 9W - 136 = 0
\]

### Step 4: Factor the quadratic equation
We need to factor \( W^2 + 9W - 136 = 0 \).

We are looking for two numbers that multiply to give \(-136\) and add up to \(9\). The correct pair is \(17\) and \(-8\) because:

\[
17 \times -8 = -136 \quad \text{and} \quad 17 + (-8) = 9
\]

Thus, the quadratic equation factors as:

\[
(W + 17)(W - 8) = 0
\]

### Step 5: Solve for \( W \)
Set each factor equal to 0:

\[
W + 17 = 0 \quad \text{or} \quad W - 8 = 0
\]

Solving these gives:

\[
W = -17 \quad \text{or} \quad W = 8
\]

Since the width cannot be negative, we take \( W = 8 \).

### Step 6: Solve for \( L \)
Substitute \( W = 8 \) back into \( L = W + 9 \):

\[
L = 8 + 9 = 17
\]

### Final Answer:
The dimensions of the backyard are:
- Width \( W = 8 \) meters.
- Length \( L = 17 \) meters.

### Conclusion:
The dimensions that make the area equal to 136 square meters are 8 meters (width) and 17 meters (length).

Would you like more details or have any questions?

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**Related Questions:**
1. How would the dimensions change if the length were 12 meters more than the width?
2. Can the quadratic equation \( W^2 + 9W - 136 = 0 \) be solved using the quadratic formula? 
3. What would the area be if the width was doubled?
4. How can you confirm the solution by recalculating the area with the dimensions found?
5. How does factoring compare to solving quadratic equations by completing the square?

**Tip:** Factoring is a fast and efficient method to solve quadratic equations, but it only works when the quadratic can be factored neatly into integer values.

The length of a rectangular backyard is 9 meters more than the width. What are the dimensions of the garden that will make the area equal to 136 m²?

This problem involves determining the dimensions of a rectangular garden where the length is 9 meters more than the width and the area is 136 square meters. The solution demonstrates the use of algebra, specifically quadratic equations and factoring, to find the width and length of the garden.

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