Math Problem Statement
Solution
The worksheet focuses on proving segment relationships using properties such as equality, congruence, and postulates. Let's break down and confirm the answers, filling in the missing steps where necessary.
Part 1: Justify Each Statement
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Q = Q
Reason: Property of Equality (This is the reflexive property of equality, where any quantity is equal to itself.) -
If AB ≅ BC and BC ≅ CE, then AB ≅ CE.
Reason: Property of Congruence (This follows the transitive property of congruence: if two segments are congruent to a third one, they are congruent to each other.) -
If Q is between P and R, then PR = PQ + QR.
Reason: Postulate (This is the Segment Addition Postulate, which states that the sum of the parts equals the whole.) -
If AB + BC = EF + FG and AB + BC = AC, then EF + FG = AC.
Reason: Property of Equality (This is an application of the transitive property of equality.)
Part 2: Complete the Proof
Given: SU ≅ LR, TU ≅ LN.
Prove: ST ≅ NR.
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SU ≅ LR, TU ≅ LN
Reason: Given. -
SU + TU = ST, LR + LN = NR
Reason: Definition of congruent segments. -
ST = NR
Reason: Property of Equality (since both sides of the equation represent the sums of congruent segments). -
**Substitute
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Math Problem Analysis
Mathematical Concepts
Geometry
Congruence
Properties of Equality
Formulas
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Theorems
Segment Addition Postulate
Properties of Congruence
Transitive Property
Suitable Grade Level
Grades 9-10
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