Math Problem Statement

Prove that x is an odd integer if and only if 5x − 1 is an even integer

Solution

To prove that xx is an odd integer if and only if 5x15x - 1 is an even integer, we need to demonstrate both implications:

1. If xx is an odd integer, then 5x15x - 1 is an even integer.

Assume xx is an odd integer. By definition, an odd integer can be expressed as: x=2k+1x = 2k + 1 for some integer kk.

Now, substitute this into the expression 5x15x - 1: 5x1=5(2k+1)15x - 1 = 5(2k + 1) - 1 Expanding this: 5x1=10k+51=10k+45x - 1 = 10k + 5 - 1 = 10k + 4 Notice that 10k+410k + 4 can be factored as: 5x1=2(5k+2)5x - 1 = 2(5k + 2) Since 5k+25k + 2 is an integer, 5x15x - 1 is twice some integer, which means it is an even integer.

Thus, if xx is an odd integer, 5x15x - 1 is indeed an even integer.

2. If 5x15x - 1 is an even integer, then xx is an odd integer.

Assume 5x15x - 1 is an even integer. This means: 5x1=2m5x - 1 = 2m for some integer mm.

To solve for xx, add 1 to both sides: 5x=2m+15x = 2m + 1 Now divide by 5: x=2m+15x = \frac{2m + 1}{5} Here, 2m+12m + 1 is an odd integer (since the sum of an even and an odd number is odd), and an odd integer divided by 5 will result in another integer only if xx is odd.

This implies that xx must be of the form x=2k+1x = 2k + 1 for some integer kk, which means xx is an odd integer.

Thus, if 5x15x - 1 is an even integer, xx must be an odd integer.

Conclusion

We have shown both directions:

  1. If xx is an odd integer, then 5x15x - 1 is an even integer.
  2. If 5x15x - 1 is an even integer, then xx is an odd integer.

Therefore, xx is an odd integer if and only if 5x15x - 1 is an even integer.

Would you like more details or have any questions? Here are some related questions you might find interesting:

  1. What happens if xx is an even integer in the expression 5x15x - 1?
  2. How would the proof change if the expression were 5x+15x + 1 instead of 5x15x - 1?
  3. Can you prove that if xx is even, then 5x15x - 1 is odd?
  4. How does this proof apply to other linear functions of xx?
  5. Can you find another similar statement involving odd/even integers and a different linear combination?

Tip: Remember that even and odd integers have a predictable behavior when added, subtracted, or multiplied, which is helpful in proving statements involving parity.

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Math Problem Analysis

Mathematical Concepts

Number Theory
Parity (Odd and Even Numbers)
Logical Equivalence

Formulas

Odd integer: x = 2k + 1
Expression: 5x - 1

Theorems

Properties of Odd and Even Numbers

Suitable Grade Level

Grades 9-12