Math Problem Statement
Prove that x is an odd integer if and only if 5x − 1 is an even integer
Solution
To prove that is an odd integer if and only if is an even integer, we need to demonstrate both implications:
1. If is an odd integer, then is an even integer.
Assume is an odd integer. By definition, an odd integer can be expressed as: for some integer .
Now, substitute this into the expression : Expanding this: Notice that can be factored as: Since is an integer, is twice some integer, which means it is an even integer.
Thus, if is an odd integer, is indeed an even integer.
2. If is an even integer, then is an odd integer.
Assume is an even integer. This means: for some integer .
To solve for , add 1 to both sides: Now divide by 5: Here, is an odd integer (since the sum of an even and an odd number is odd), and an odd integer divided by 5 will result in another integer only if is odd.
This implies that must be of the form for some integer , which means is an odd integer.
Thus, if is an even integer, must be an odd integer.
Conclusion
We have shown both directions:
- If is an odd integer, then is an even integer.
- If is an even integer, then is an odd integer.
Therefore, is an odd integer if and only if is an even integer.
Would you like more details or have any questions? Here are some related questions you might find interesting:
- What happens if is an even integer in the expression ?
- How would the proof change if the expression were instead of ?
- Can you prove that if is even, then is odd?
- How does this proof apply to other linear functions of ?
- Can you find another similar statement involving odd/even integers and a different linear combination?
Tip: Remember that even and odd integers have a predictable behavior when added, subtracted, or multiplied, which is helpful in proving statements involving parity.
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Math Problem Analysis
Mathematical Concepts
Number Theory
Parity (Odd and Even Numbers)
Logical Equivalence
Formulas
Odd integer: x = 2k + 1
Expression: 5x - 1
Theorems
Properties of Odd and Even Numbers
Suitable Grade Level
Grades 9-12