Math Problem Statement

1. Let \( \{x_n\} \) be a sequence defined by \( x_n = \frac{n}{n+1} \). Show that \( \{x_n\} \) is Cauchy. 2. Show that the sequence defined by \( x_n = 3 + \frac{1}{n} \) is Cauchy. 3. Determine if the sequence defined by \( x_n = (-1)^n + \frac{1}{n} \) is a Cauchy sequence. 4. Prove that the sequence defined by \( x_n = \sqrt{n+1} - \sqrt{n} \) is a Cauchy sequence.

Solution

To solve these problems, let's go through each exercise one by one, showing that each sequence is a Cauchy sequence. A sequence {xn}\{x_n\} is Cauchy if, for every ϵ>0\epsilon > 0, there exists an integer NN such that for all m,nNm, n \geq N, xnxm<ϵ|x_n - x_m| < \epsilon.

1. Sequence xn=nn+1x_n = \frac{n}{n+1}

To show that {xn}\{x_n\} is Cauchy:

  1. Calculate xnxm|x_n - x_m|: xn=nn+1andxm=mm+1x_n = \frac{n}{n+1} \quad \text{and} \quad x_m = \frac{m}{m+1} Then, xnxm=nn+1mm+1|x_n - x_m| = \left|\frac{n}{n+1} - \frac{m}{m+1}\right|
  2. Rewrite the expression with a common denominator and simplify.
  3. Show that as n,mn, m \to \infty, xnxm|x_n - x_m| can be made arbitrarily small, proving that the sequence is Cauchy.

2. Sequence xn=3+1nx_n = 3 + \frac{1}{n}

To show that {xn}\{x_n\} is Cauchy:

  1. Calculate xnxm|x_n - x_m|: xnxm=(3+1n)(3+1m)=1n1m|x_n - x_m| = \left|(3 + \frac{1}{n}) - (3 + \frac{1}{m})\right| = \left|\frac{1}{n} - \frac{1}{m}\right|
  2. As n,mn, m \to \infty, both 1n\frac{1}{n} and 1m\frac{1}{m} approach zero.
  3. Show that xnxm|x_n - x_m| can be made arbitrarily small for large n,mn, m, which proves that the sequence is Cauchy.

3. Sequence xn=(1)n+1nx_n = (-1)^n + \frac{1}{n}

To determine if {xn}\{x_n\} is Cauchy:

  1. Calculate xnxm|x_n - x_m|: xnxm=(1)n+1n((1)m+1m)|x_n - x_m| = \left|(-1)^n + \frac{1}{n} - \left((-1)^m + \frac{1}{m}\right)\right|
  2. This sequence does not converge, as it oscillates due to the (1)n(-1)^n term.
  3. Since the sequence does not converge, it is not Cauchy.

4. Sequence xn=n+1nx_n = \sqrt{n+1} - \sqrt{n}

To show that {xn}\{x_n\} is Cauchy:

  1. Rewrite the expression: xn=n+1n=1n+1+nx_n = \sqrt{n+1} - \sqrt{n} = \frac{1}{\sqrt{n+1} + \sqrt{n}}
  2. Calculate xnxm|x_n - x_m| for large nn and mm.
  3. Show that as n,mn, m \to \infty, the difference xnxm|x_n - x_m| becomes arbitrarily small, proving that the sequence is Cauchy.

Would you like to see detailed steps for any specific part?


Further Related Questions:

  1. What are the general properties of a Cauchy sequence?
  2. How does the definition of Cauchy sequence relate to convergence?
  3. What is the relationship between bounded sequences and Cauchy sequences?
  4. Can an unbounded sequence be Cauchy? Explain with examples.
  5. How does the presence of oscillatory terms affect the convergence of a sequence?

Tip: For a sequence to be Cauchy in R\mathbb{R}, it must converge. Hence, checking if a sequence converges can simplify proving it's Cauchy.

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Math Problem Analysis

Mathematical Concepts

Sequences
Cauchy Sequences
Convergence

Formulas

\( x_n = \frac{n}{n+1} \)
\( x_n = 3 + \frac{1}{n} \)
\( x_n = (-1)^n + \frac{1}{n} \)
\( x_n = \sqrt{n+1} - \sqrt{n} \)

Theorems

Definition of Cauchy Sequence

Suitable Grade Level

College Level