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The image contains a proof related to geometry, specifically about angles. The information visible is as follows:

- **Given:** ∠1 ≅ ∠3
- **Prove:** ∠AEC ≅ ∠BEC
- **Method:** Using the Reflexive Property

### Explanation:

To prove that ∠AEC is congruent to ∠BEC, we can use the **Reflexive Property**, which states that any geometric entity is congruent to itself. Here's how you can proceed with the proof:

#### Statements:
1. ∠1 ≅ ∠3 (Given)
2. EC ≅ EC (Reflexive Property, EC is the shared segment between the two triangles AEC and BEC)
3. △AEC ≅ △BEC (By ASA - Angle-Side-Angle Congruence, since ∠1 ≅ ∠3, EC ≅ EC, and they share the angle at point E)
4. ∠AEC ≅ ∠BEC (CPCTC - Corresponding Parts of Congruent Triangles are Congruent)

#### Reasons:
1. Given
2. Reflexive Property
3. ASA Congruence Postulate
4. CPCTC

Would you like further details on how to complete the proof in this format or on another related topic?

### Related questions:
1. What is the Reflexive Property in geometry, and how is it applied in congruence proofs?
2. How does the ASA (Angle-Side-Angle) Congruence Postulate work in triangle congruence?
3. What is the CPCTC (Corresponding Parts of Congruent Triangles are Congruent) theorem used for?
4. Can congruence be proven using other methods besides ASA, like SSS or SAS?
5. What other properties of angles and segments are commonly used in geometric proofs?

### Tip:
Always make sure to identify shared sides or angles in geometric figures, as this can simplify proofs using congruence theorems.

Prove ∠AEC ≅ ∠BEC given ∠1 ≅ ∠3 using the Reflexive Property.

This geometry proof demonstrates how to prove that ∠AEC ≅ ∠BEC given ∠1 ≅ ∠3, by using the Reflexive Property, ASA Congruence, and CPCTC. Ideal for students in Grades 8-10.

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