Math Problem Statement

prove every real number in set (0,1) is an interior point of (0,1)

Solution

To prove that every real number in the set (0,1)(0, 1) is an interior point of (0,1)(0, 1), we can rely on the definition of an interior point.

Definition of an Interior Point:

A point xx is said to be an interior point of a set SS if there exists an open interval around xx that is entirely contained within SS. In other words, there is some ε>0\varepsilon > 0 such that the interval (xε,x+ε)(x - \varepsilon, x + \varepsilon) is a subset of SS.

Proof:

  1. Let x(0,1)x \in (0, 1):

    • Consider any point x(0,1)x \in (0, 1). By definition, xx is a real number such that 0<x<10 < x < 1.
  2. Find an ε\varepsilon such that the interval (xε,x+ε)(0,1)(x - \varepsilon, x + \varepsilon) \subset (0, 1):

    • Since xx is strictly between 0 and 1, we know that there is some positive distance between xx and the endpoints of the interval 0 and 1.
    • Specifically, the distance from xx to 0 is x0=xx - 0 = x, and the distance from xx to 1 is 1x1 - x.
    • Let ε=min(x,1x)\varepsilon = \min(x, 1 - x). This ensures that ε\varepsilon is the smaller of the distances between xx and the two endpoints of the interval (0 and 1).
  3. Verify that the interval (xε,x+ε)(x - \varepsilon, x + \varepsilon) lies within (0,1)(0, 1):

    • By construction, εx\varepsilon \leq x and ε1x\varepsilon \leq 1 - x.
    • Therefore:
      • xε0x - \varepsilon \geq 0 (so the left endpoint of the interval is greater than or equal to 0).
      • x+ε1x + \varepsilon \leq 1 (so the right endpoint of the interval is less than or equal to 1).
    • This shows that the open interval (xε,x+ε)(x - \varepsilon, x + \varepsilon) is completely contained within (0,1)(0, 1).
  4. Conclusion:

    • Since for every x(0,1)x \in (0, 1), we can find an open interval (xε,x+ε)(0,1)(x - \varepsilon, x + \varepsilon) \subset (0, 1), we conclude that every point in (0,1)(0, 1) is an interior point of (0,1)(0, 1).

Thus, every real number in (0,1)(0, 1) is an interior point of (0,1)(0, 1).

Would you like further details on any part of this explanation?


Here are 5 related questions to expand on this topic:

  1. How does the definition of an open set relate to interior points?
  2. Can you prove whether 00 or 11 are interior points of [0,1][0, 1]?
  3. How would you prove that a closed interval, like [0,1][0, 1], has no interior points at its boundary?
  4. What is the relationship between interior points and boundary points of a set?
  5. How does the concept of interior points apply to higher-dimensional spaces, such as in R2\mathbb{R}^2?

Tip: When proving properties about sets and intervals, always start with the definitions and verify conditions step by step.

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Math Problem Analysis

Mathematical Concepts

Real Analysis
Topology
Intervals

Formulas

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Theorems

Interior Point Definition
Open Interval Theorem

Suitable Grade Level

Undergraduate Level (Real Analysis)