Math Problem Statement

If u=(x^2+y^2/x+y),show that (du/dx-du/dy)^2 = 4(1-du/dx-du/dy)

Solution

Given the expression for uu:

u=x2+y2xyu = \frac{x^2 + \frac{y^2}{x}}{y}

We need to show that:

(dudxdudy)2=4(1dudxdudy)\left(\frac{du}{dx} - \frac{du}{dy}\right)^2 = 4 \left(1 - \frac{du}{dx} - \frac{du}{dy}\right)

Step 1: Compute dudx\frac{du}{dx}

We differentiate uu with respect to xx, applying the quotient rule and chain rule as needed.

Since the expression for uu contains both xx and yy, we proceed by first finding partial derivatives.

Step 2: Compute dudy\frac{du}{dy}

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Math Problem Analysis

Mathematical Concepts

Calculus
Partial Derivatives
Quotient Rule
Chain Rule

Formulas

u = (x^2 + y^2) / (x + y)
du/dx = d/dx [(x^2 + y^2) / (x + y)]
du/dy = d/dy [(x^2 + y^2) / (x + y)]
(du/dx - du/dy)^2 = 4(1 - du/dx - du/dy)

Theorems

Quotient Rule for Derivatives
Chain Rule for Differentiation

Suitable Grade Level

College Level Calculus