Math Problem Statement

prove that a number's square cannot end with two consecutive odd digits

Solution

To prove that a number's square cannot end with two consecutive odd digits, let's consider the following:

Step 1: Represent the number

Let nn be any integer, and we want to prove that n2n^2 (the square of nn) cannot end with two consecutive odd digits.

Step 2: Analyze the last digit of nn

We know that the last digit of n2n^2 depends only on the last digit of nn. Thus, we can reduce the problem by examining the possible last digits of nn, which are 0,1,2,3,4,5,6,7,8,90, 1, 2, 3, 4, 5, 6, 7, 8, 9, and compute the corresponding last two digits of n2n^2.

Step 3: Calculate last two digits of n2n^2

For each nmod10n \mod 10, compute n2mod100n^2 \mod 100 (i.e., the last two digits of the square of nn):

  1. n=0n2=02=00n = 0 \Rightarrow n^2 = 0^2 = 00
  2. n=1n2=12=01n = 1 \Rightarrow n^2 = 1^2 = 01
  3. n=2n2=22=04n = 2 \Rightarrow n^2 = 2^2 = 04
  4. n=3n2=32=09n = 3 \Rightarrow n^2 = 3^2 = 09
  5. n=4n2=42=16n = 4 \Rightarrow n^2 = 4^2 = 16
  6. n=5n2=52=25n = 5 \Rightarrow n^2 = 5^2 = 25
  7. n=6n2=62=36n = 6 \Rightarrow n^2 = 6^2 = 36
  8. n=7n2=72=49n = 7 \Rightarrow n^2 = 7^2 = 49
  9. n=8n2=82=64n = 8 \Rightarrow n^2 = 8^2 = 64
  10. n=9n2=92=81n = 9 \Rightarrow n^2 = 9^2 = 81

Step 4: Check the last two digits

Now let's list the last two digits of each square:

  • 02=000^2 = 00
  • 12=011^2 = 01
  • 22=042^2 = 04
  • 32=093^2 = 09
  • 42=164^2 = 16
  • 52=255^2 = 25
  • 62=366^2 = 36
  • 72=497^2 = 49
  • 82=648^2 = 64
  • 92=819^2 = 81

Step 5: Conclusion

From this list, we see that no square of a number ends with two consecutive odd digits. The possible last digits of squares are: 00,01,04,09,16,25,36,49,64,8100, 01, 04, 09, 16, 25, 36, 49, 64, 81. None of these end with two consecutive odd digits (such as 11, 33, 55, 77, or 99).

Thus, we have proved that a number's square cannot end with two consecutive odd digits.


Would you like any more details on this proof or any part clarified?

Related questions:

  1. Why can't a square of a number end with 77?
  2. How do the last two digits of squares follow specific patterns?
  3. Can a square of a number end with two even digits?
  4. What other properties can be derived from the last digits of a number's square?
  5. How can this property be generalized for bases other than 10?

Tip:

When solving number theory problems, exploring modular arithmetic is a powerful tool to detect patterns efficiently.

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Math Problem Analysis

Mathematical Concepts

Number Theory
Modular Arithmetic
Properties of Squares

Formulas

n^2 mod 100
n^2 = (n mod 10)^2

Theorems

Properties of Squares of Integers

Suitable Grade Level

Grades 9-12