Math Problem Statement

  1. Prove that lim xsin (1/x)=0

Solution

To prove that

limx0xsin(1x)=0,\lim_{x \to 0} x \sin\left(\frac{1}{x}\right) = 0,

we can use the Squeeze Theorem (also known as the Sandwich Theorem).

Step-by-Step Proof

  1. Understand the Function Behavior:

    The sine function, sin(1x)\sin\left(\frac{1}{x}\right), oscillates between 1-1 and 11 for all values of xx, so we have:

    1sin(1x)1.-1 \leq \sin\left(\frac{1}{x}\right) \leq 1.

  2. Multiply by xx:

    Multiply the entire inequality by xx. Since xx can be positive or negative, we'll consider two cases:

    • For x>0x > 0:

      xxsin(1x)x.-x \leq x \sin\left(\frac{1}{x}\right) \leq x.

    • For x<0x < 0:

      xxsin(1x)x.x \leq x \sin\left(\frac{1}{x}\right) \leq -x.

    Notice that these inequalities hold for xx approaching 0 from either side.

  3. Consider the Limit of the Bounds:

    As x0x \to 0, both xx and x-x approach 0. Therefore:

    limx0+x=0andlimx0+x=0.\lim_{x \to 0^+} x = 0 \quad \text{and} \quad \lim_{x \to 0^+} -x = 0.

    Similarly,

    limx0x=0andlimx0x=0.\lim_{x \to 0^-} x = 0 \quad \text{and} \quad \lim_{x \to 0^-} -x = 0.

    Hence, in either case:

    limx0xsin(1x)=0.\lim_{x \to 0} x \sin\left(\frac{1}{x}\right) = 0.

  4. Apply the Squeeze Theorem:

    Since xsin(1x)x \sin\left(\frac{1}{x}\right) is squeezed between two functions that both tend to 0 as x0x \to 0, by the Squeeze Theorem:

    limx0xsin(1x)=0.\lim_{x \to 0} x \sin\left(\frac{1}{x}\right) = 0.

This completes the proof.

Would you like any further details or explanations on this proof?

Here are 5 related questions to expand your understanding:

  1. How does the Squeeze Theorem work in different types of limits?
  2. Can you prove the limit using an epsilon-delta definition?
  3. What happens to the function xsin(1x)x \sin\left(\frac{1}{x}\right) as xx approaches infinity?
  4. How does the limit change if we replace xsin(1x)x \sin\left(\frac{1}{x}\right) with x2sin(1x)x^2 \sin\left(\frac{1}{x}\right)?
  5. What are some other common functions that require the Squeeze Theorem for limit proofs?

Tip: When working with limits involving oscillating functions, the Squeeze Theorem is a powerful tool, especially if you can bound the function between two simpler functions that have known limits.

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Math Problem Analysis

Mathematical Concepts

Limits
Squeeze Theorem
Trigonometric Functions

Formulas

-

Theorems

Squeeze Theorem

Suitable Grade Level

Undergraduate