Math Problem Statement
- Prove that lim xsin (1/x)=0
Solution
To prove that
we can use the Squeeze Theorem (also known as the Sandwich Theorem).
Step-by-Step Proof
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Understand the Function Behavior:
The sine function, , oscillates between and for all values of , so we have:
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Multiply by :
Multiply the entire inequality by . Since can be positive or negative, we'll consider two cases:
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For :
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For :
Notice that these inequalities hold for approaching 0 from either side.
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Consider the Limit of the Bounds:
As , both and approach 0. Therefore:
Similarly,
Hence, in either case:
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Apply the Squeeze Theorem:
Since is squeezed between two functions that both tend to 0 as , by the Squeeze Theorem:
This completes the proof.
Would you like any further details or explanations on this proof?
Here are 5 related questions to expand your understanding:
- How does the Squeeze Theorem work in different types of limits?
- Can you prove the limit using an epsilon-delta definition?
- What happens to the function as approaches infinity?
- How does the limit change if we replace with ?
- What are some other common functions that require the Squeeze Theorem for limit proofs?
Tip: When working with limits involving oscillating functions, the Squeeze Theorem is a powerful tool, especially if you can bound the function between two simpler functions that have known limits.
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Math Problem Analysis
Mathematical Concepts
Limits
Squeeze Theorem
Trigonometric Functions
Formulas
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Theorems
Squeeze Theorem
Suitable Grade Level
Undergraduate