Math Problem Statement

Prove the relation defined on R2 by (x1, y1) ∼ (x2, y2) if x(2/1) + y(2/1) = x(2/2) + y(2/2) is an equivalence relation.

Solution

To prove that the given relation (x1,y1)(x2,y2)(x_1, y_1) \sim (x_2, y_2), defined on R2\mathbb{R}^2 by the condition x1+y1=x2+y2x_1 + y_1 = x_2 + y_2, is an equivalence relation, we must verify the three properties of an equivalence relation: reflexivity, symmetry, and transitivity.


1. Reflexivity

A relation is reflexive if (x1,y1)(x1,y1)(x_1, y_1) \sim (x_1, y_1) for all (x1,y1)R2(x_1, y_1) \in \mathbb{R}^2.

  • From the definition, (x1,y1)(x1,y1)(x_1, y_1) \sim (x_1, y_1) means x1+y1=x1+y1x_1 + y_1 = x_1 + y_1.
  • This is clearly true because equality holds for any (x1,y1)(x_1, y_1).

Thus, the relation is reflexive.


2. Symmetry

A relation is symmetric if (x1,y1)(x2,y2)(x_1, y_1) \sim (x_2, y_2) implies (x2,y2)(x1,y1)(x_2, y_2) \sim (x_1, y_1).

  • From the definition, (x1,y1)(x2,y2)(x_1, y_1) \sim (x_2, y_2) means x1+y1=x2+y2x_1 + y_1 = x_2 + y_2.
  • By the symmetry of equality, x2+y2=x1+y1x_2 + y_2 = x_1 + y_1 also holds.
  • Therefore, if (x1,y1)(x2,y2)(x_1, y_1) \sim (x_2, y_2), it follows that (x2,y2)(x1,y1)(x_2, y_2) \sim (x_1, y_1).

Thus, the relation is symmetric.


3. Transitivity

A relation is transitive if (x1,y1)(x2,y2)(x_1, y_1) \sim (x_2, y_2) and (x2,y2)(x3,y3)(x_2, y_2) \sim (x_3, y_3) together imply (x1,y1)(x3,y3)(x_1, y_1) \sim (x_3, y_3).

  • From the definition:
    • (x1,y1)(x2,y2)(x_1, y_1) \sim (x_2, y_2) implies x1+y1=x2+y2x_1 + y_1 = x_2 + y_2.
    • (x2,y2)(x3,y3)(x_2, y_2) \sim (x_3, y_3) implies x2+y2=x3+y3x_2 + y_2 = x_3 + y_3.
  • From these two equalities, x1+y1=x3+y3x_1 + y_1 = x_3 + y_3 follows by the transitivity of equality.
  • Hence, (x1,y1)(x3,y3)(x_1, y_1) \sim (x_3, y_3).

Thus, the relation is transitive.


Conclusion

Since the relation satisfies reflexivity, symmetry, and transitivity, it is an equivalence relation.


Would you like me to expand on any part of the proof or provide examples? 😊


Here are 5 related questions to deepen understanding:

  1. What are equivalence classes of the relation (x1,y1)(x2,y2)(x_1, y_1) \sim (x_2, y_2) under this equivalence?
  2. How can this equivalence relation be applied in geometry or algebra?
  3. Is the sum x+yx + y in the equivalence relation invariant under certain transformations?
  4. Can you define another equivalence relation on R2\mathbb{R}^2 based on different operations (e.g., multiplication)?
  5. How would this relation change if we replaced x1+y1=x2+y2x_1 + y_1 = x_2 + y_2 with x12+y12=x22+y22x_1^2 + y_1^2 = x_2^2 + y_2^2?

Tip: Always verify the properties of an equivalence relation (reflexivity, symmetry, transitivity) systematically to ensure clarity in proofs.

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Math Problem Analysis

Mathematical Concepts

Equivalence Relations
Algebra
Relations on R^2

Formulas

x1 + y1 = x2 + y2

Theorems

Reflexivity
Symmetry
Transitivity

Suitable Grade Level

Grades 10-12