Math Problem Statement
Prove the relation defined on R2 by (x1, y1) ∼ (x2, y2) if x(2/1) + y(2/1) = x(2/2) + y(2/2) is an equivalence relation.
Solution
To prove that the given relation , defined on by the condition , is an equivalence relation, we must verify the three properties of an equivalence relation: reflexivity, symmetry, and transitivity.
1. Reflexivity
A relation is reflexive if for all .
- From the definition, means .
- This is clearly true because equality holds for any .
Thus, the relation is reflexive.
2. Symmetry
A relation is symmetric if implies .
- From the definition, means .
- By the symmetry of equality, also holds.
- Therefore, if , it follows that .
Thus, the relation is symmetric.
3. Transitivity
A relation is transitive if and together imply .
- From the definition:
- implies .
- implies .
- From these two equalities, follows by the transitivity of equality.
- Hence, .
Thus, the relation is transitive.
Conclusion
Since the relation satisfies reflexivity, symmetry, and transitivity, it is an equivalence relation.
Would you like me to expand on any part of the proof or provide examples? 😊
Here are 5 related questions to deepen understanding:
- What are equivalence classes of the relation under this equivalence?
- How can this equivalence relation be applied in geometry or algebra?
- Is the sum in the equivalence relation invariant under certain transformations?
- Can you define another equivalence relation on based on different operations (e.g., multiplication)?
- How would this relation change if we replaced with ?
Tip: Always verify the properties of an equivalence relation (reflexivity, symmetry, transitivity) systematically to ensure clarity in proofs.
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Math Problem Analysis
Mathematical Concepts
Equivalence Relations
Algebra
Relations on R^2
Formulas
x1 + y1 = x2 + y2
Theorems
Reflexivity
Symmetry
Transitivity
Suitable Grade Level
Grades 10-12
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