Let's break down the problem:

1. State A has:

   • Population: 23,250
   • Representatives: 15
   • Average constituency = $\frac{23,250}{15} = 1,550$

2. State B has:

   • Population: 22,750
   • Representatives: 14
   • Average constituency = $\frac{22,750}{14} = 1,625$

Questions:

1. Which state is more poorly represented?

   • Since a higher average constituency means less representation per person, State B is more poorly represented with an average constituency of 1,625 compared to 1,550 for State A.

2. Absolute unfairness:

   • Absolute unfairness = Difference between the average constituencies.
   • $1,625 - 1,550 = 75$

3. Relative unfairness:

   • Relative unfairness = $\frac{\text{Absolute unfairness}}{\text{Smaller average constituency}} \times 100$
   • $\frac{75}{1,550} \times 100 = 4.839 \%$

So, the relative unfairness is 4.839%, rounded to three decimal places.

Would you like further clarification or more details on any of these steps?

Related Questions:

1. How does population size affect representation fairness?
2. What other methods can be used to ensure fair representation?
3. Why is State B considered more poorly represented in this case?
4. Can the relative unfairness be higher than 100%?
5. How do changes in population affect representation calculations?

Tip: Absolute unfairness measures the raw difference, while relative unfairness compares it proportionally to the representation size.