Math Problem Statement

Let \( f \) be a real-valued function defined on an open interval \( I = (a, b) \). Assume that \( f \) is monotonically increasing (nondecreasing), meaning \( f(x) \leq f(y) \) for all \( x < y \) within \( I \). For \( c \in I \), consider the jump of \( f \) at \( c \), defined by \[ [f(c)] := \lim_{x \to c^+} f(x) - \lim_{x \to c^-} f(x) \]. Prove that the one-sided limits in this equation exist for all \( c \in I \), and show that \( [f(c)] \geq 0 \). Furthermore, prove that \( [f(c)] = 0 \) if and only if \( f \) is continuous at \( c \).

Solution

The assignment displayed in your screenshot contains a problem from Spivak's Calculus (Problem 8.8) focused on proving properties of a monotonically increasing function ff defined on an open interval I=(a,b)I = (a, b). Here’s a breakdown of the problem requirements:

Problem Statement Analysis

  1. Monotonicity: We assume ff is monotonically increasing, meaning f(x)f(y)f(x) \leq f(y) for all x<yx < y within the interval II.
  2. Jump Discontinuity Definition: For any cIc \in I, the jump of ff at cc is given by: [f(c)]:=limxc+f(x)limxcf(x)[f(c)] := \lim_{x \to c^+} f(x) - \lim_{x \to c^-} f(x)

Required Proofs

  • Part (a): Show that the one-sided limits limxc+f(x)\lim_{x \to c^+} f(x) and limxcf(x)\lim_{x \to c^-} f(x) exist for each cIc \in I.
  • Part (b): Prove that [f(c)]0[f(c)] \geq 0 and that [f(c)]=0[f(c)] = 0 if and only if ff is continuous at cc.

Strategy for Solutions

  1. One-Sided Limits: Since ff is monotonically increasing, it implies that the left and right limits as xx approaches cc should exist due to the bounded behavior of monotonically increasing functions on intervals.

  2. Jump Calculation:

    • If there’s a discontinuity at cc, the jump [f(c)][f(c)] captures this gap.
    • Since ff is increasing, the jump [f(c)][f(c)] should be non-negative because f(x)f(x) does not decrease on II.
  3. Continuity Condition:

    • If ff is continuous at cc, then limxc+f(x)=limxcf(x)=f(c)\lim_{x \to c^+} f(x) = \lim_{x \to c^-} f(x) = f(c), leading to [f(c)]=0[f(c)] = 0.
    • Conversely, if [f(c)]=0[f(c)] = 0, then ff must be continuous at cc since there’s no gap between the left and right limits.

Would you like a detailed solution with formal proofs for each part?

Follow-Up Questions

  1. What is the general impact of a function's monotonicity on the existence of one-sided limits?
  2. How does the concept of jump discontinuity relate to the continuity of functions?
  3. Can the result [f(c)]0[f(c)] \geq 0 be generalized to all monotonically increasing functions?
  4. What would happen if ff were monotonically decreasing instead?
  5. How do these properties change if the function is not defined on an open interval?

Tip

In problems involving continuity and limits, always start by examining the behavior of the function as it approaches points from both directions. This helps in understanding discontinuities and ensuring proper limit evaluation.

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Math Problem Analysis

Mathematical Concepts

Monotonic functions
Limits
Continuity
Jump discontinuity

Formulas

\( f(x) \leq f(y) \) for all \( x < y \)
\( [f(c)] := \lim_{x \to c^+} f(x) - \lim_{x \to c^-} f(x) \)

Theorems

Existence of one-sided limits for monotonic functions
Definition of jump discontinuity

Suitable Grade Level

University-level calculus