Math Problem Statement
Solution
Let's solve the problem step by step. We are given three functions , , and . We need to prove three statements based on the composition of these functions.
1. Prove: If and are one-to-one, then is one-to-one.
Proof:
- Let and be injective (one-to-one functions).
- To prove that is injective, assume for some .
- Since is injective, we can conclude that .
- Since is injective, .
- Thus, is injective (one-to-one).
2. Prove: If and are onto, then is onto.
Proof:
- Let and be surjective (onto functions).
- To prove that is surjective, take any . Since is surjective, there exists some such that .
- Since is surjective, there exists some such that .
- Therefore, , which shows that for every , there exists an such that .
- Thus, is surjective (onto).
3. Prove: .
Proof:
- We need to show that .
- By the definition of composition of functions, we have:
- ,
- .
- Since both sides simplify to , the equality holds.
- Therefore, .
These are the required proofs for the given statements.
Do you want more details on any of the steps or have any questions?
Here are some related questions for further practice:
- Can you prove that the composition of two surjective functions is surjective?
- How would you define the inverse of a composition of two injective functions?
- What is the general property of function composition with respect to associativity?
- If is not surjective but is, is surjective?
- Can a function be injective but not surjective? Provide an example.
Tip: Always pay attention to how function properties (injectivity and surjectivity) transfer through composition, as these are fundamental in proving larger properties of composed functions.
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Math Problem Analysis
Mathematical Concepts
Function Composition
Injectivity (One-to-One)
Surjectivity (Onto)
Associativity of Functions
Formulas
(g ∘ f)(x) = g(f(x))
(h ∘ g) ∘ f = h ∘ (g ∘ f)
Theorems
Theorem: Composition of injective functions is injective
Theorem: Composition of surjective functions is surjective
Associativity of function composition
Suitable Grade Level
Grades 11-12 or University-level
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