Math Problem Statement
) If π(π§) and π(π§) Μ Μ Μ Μ Μ Μ are both analytic.prove that π(π§) is constant.
Solution
To prove that if both and are analytic, then must be constant, we can use the fact that an analytic function satisfies the Cauchy-Riemann equations and apply some properties related to complex differentiability.
Let , where and are the real and imaginary parts of , respectively. Since is analytic, and satisfy the Cauchy-Riemann equations:
Since is also analytic, we can express as , and for this to be analytic, and must also satisfy the Cauchy-Riemann equations:
Now we have two sets of conditions:
- From the analyticity of :
- From the analyticity of :
Comparing these two sets of equations, we observe that they imply: and
Thus, is constant. With being constant, the Cauchy-Riemann equations imply that must also be constant, because the partial derivatives of would then be zero as well.
Therefore, is constant.
This completes the proof that if both and are analytic, then must be constant.
Would you like more details or have any questions?
Here are some related questions you might find interesting:
- How do the Cauchy-Riemann equations characterize the analyticity of a function?
- What is the significance of a function being constant in complex analysis?
- Can a function that is real-valued and analytic be non-constant?
- How does the concept of harmonic functions relate to analytic functions?
- What is the maximum modulus principle in complex analysis?
Tip: In complex analysis, analyticity is a powerful property, and the Cauchy-Riemann equations serve as a fundamental tool to determine if a function is analytic.
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Math Problem Analysis
Mathematical Concepts
Complex Analysis
Analytic Functions
Complex Differentiability
Formulas
Cauchy-Riemann Equations: βu/βx = βv/βy and βu/βy = -βv/βx
Theorems
Cauchy-Riemann Equations
Constant Function Theorem in Complex Analysis
Suitable Grade Level
Advanced Undergraduate - Graduate Level
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