Math Problem Statement
Solution
Let's solve this by proving each part using the principle of mathematical induction.
Part (a)
Statement:
For all positive integers :
Proof by Induction:
-
Base Case (): The base case holds true.
-
Inductive Step:
- Assume the formula holds for some integer , i.e.,
- Now, prove that it holds for , i.e., show that:
- Starting with the inductive hypothesis:
- Factor out from the right side:
- This matches the required expression for .
Since both the base case and inductive step are proven, the statement holds for all positive integers .
Part (b)
Statement:
For all positive integers :
Proof by Induction:
-
Base Case (): The base case holds true.
-
Inductive Step:
- Assume the formula holds for some integer , i.e.,
- Now, prove that it holds for , i.e., show that:
- Starting with the inductive hypothesis:
- Factor out from the right side:
- This matches the required expression for .
Since both the base case and inductive step are proven, the statement holds for all positive integers .
Would you like further details or explanations?
Here are some related questions for practice:
- What is the principle of mathematical induction?
- How would you prove a different series sum using induction?
- Can induction be used to prove inequalities?
- What are common errors to avoid in inductive proofs?
- How does induction differ from other proof techniques?
Tip: When using induction, always start with a clear base case and ensure each step logically follows from the assumption.
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Mathematical Induction
Summation of Series
Formulas
Sum of first n natural numbers: S = n(n + 1) / 2
Sum of first n terms of sequence of products: S = n(n + 1)(n + 2) / 3
Theorems
Principle of Mathematical Induction
Suitable Grade Level
Grades 11-12