A rock is projected from the edge of the top
of a building with an initial velocity of 20 m/s
at an angle of 33◦
above the horizontal. The
rock strikes the ground a horizontal distance
of 94 m from the base of the building.
The acceleration of gravity is 9.8 m/s
2
.
Assume: The ground is level and that the
side of the building is vertical. Neglect air
friction.

what is the vertical component of the rocks velocity

To find the vertical component of the rock's velocity, we use the initial velocity and the angle of projection. The vertical component of the velocity (\(v_{y0}\)) can be determined using the following equation:

\[
v_{y0} = v_0 \sin \theta
\]

Where:
- \(v_0 = 20 \, \text{m/s}\) is the initial velocity of the rock.
- \(\theta = 33^\circ\) is the angle of projection.

Now, let's calculate \(v_{y0}\):

\[
v_{y0} = 20 \sin 33^\circ
\]

Let me calculate this for you.The vertical component of the rock's initial velocity is approximately \(10.89 \, \text{m/s}\).

Would you like further details or have any other questions?

Here are five related questions you might consider:
1. What is the horizontal component of the rock's velocity?
2. How long does the rock stay in the air before hitting the ground?
3. What is the height of the building?
4. What is the rock's velocity just before it hits the ground?
5. How far vertically does the rock travel during its motion?

**Tip:** The vertical and horizontal components of velocity are independent of each other in projectile motion!

A rock is projected from the edge of the top of a building with an initial velocity of 20 m/s at an angle of 33° above the horizontal. The rock strikes the ground a horizontal distance of 94 m from the base of the building. The acceleration of gravity is 9.8 m/s². Assume: The ground is level and that the side of the building is vertical. Neglect air friction. What is the vertical component of the rock's velocity?

Calculate the vertical component of a rock's velocity when launched from a building with an initial velocity of 20 m/s at an angle of 33°. This problem uses projectile motion principles and involves key formulas in trigonometry and kinematics. Suitable for Grades 10-12.

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