Math Problem Statement
A projectile of mass 0.741 kg is shot from a cannon. The end of the cannon’s barrel is at height 7.1 m, as shown in the figure. The initial velocity of the projectile is 11 m/s. The projectile rises to a maximum height of ∆y above the end of the cannon’s barrel and strikes the ground a horizontal distance ∆x past the end of the cannon’s barrel.Find the range ∆x of the projectile. The acceleration of gravity is 9.8 m/s Answer in units of m.
Solution
To find the range () of the projectile, we can apply the standard equations of projectile motion.
Step 1: Resolve the Initial Velocity into Components
The initial velocity of the projectile is given as .
Assuming the angle of projection is , the components of the initial velocity are:
- Horizontal velocity component:
- Vertical velocity component:
Since the angle is not provided, I will need clarification from you on that, or we can calculate it if given other conditions.
Step 2: Determine Time of Flight
To find the time of flight , we use the vertical motion equations.
The vertical displacement is given by: Where:
- (initial height)
- (the projectile hits the ground)
- (acceleration due to gravity)
Substituting these values, the equation becomes:
We will need the value of , which depends on the angle .
Step 3: Calculate the Range
The range is given by: Where is the horizontal velocity component and is the time of flight.
To proceed with the calculation, I need either the angle or more details on the problem setup. Could you provide that, or would you like me to assume a certain value for the angle?
Let me know if you would like more details or have questions about any step. Here are five related questions for further exploration:
- How does the angle of projection affect the range of a projectile?
- What happens to the maximum height if the initial speed is increased?
- How does the height of the barrel affect the total time of flight?
- Can air resistance significantly alter the range of the projectile in real-world conditions?
- What is the relationship between horizontal and vertical components in projectile motion?
Tip: In projectile motion, the horizontal velocity remains constant throughout the flight, while vertical velocity changes due to gravity.
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Math Problem Analysis
Mathematical Concepts
Projectile Motion
Kinematics
2D Motion
Formulas
v_{0x} = v_0 \cos \theta
v_{0y} = v_0 \sin \theta
y = y_0 + v_{0y}t - \frac{1}{2}gt^2
∆x = v_{0x} * t
Theorems
Equations of Motion for Projectiles
Suitable Grade Level
Grade 10-12
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