Math Problem Statement
Solution
The image presents a physics problem involving a baseball pitch modeled by two parametric equations:
where and represent the horizontal and vertical positions of the baseball at time in seconds, and the units are in feet.
Given Questions and Their Solutions
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(a) Calculate the horizontal velocity of the baseball at time .
- The horizontal velocity is the derivative of with respect to , which yields:
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(b) What is the horizontal velocity of the baseball when it passes over home plate?
- Since is constant, the horizontal velocity at home plate remains .
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(c) What is the vertical velocity of the baseball at time ?
- The vertical velocity is the derivative of with respect to :
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(d) Speed of the baseball when it passes over home plate
- The speed is given by the magnitude of the velocity vector, calculated as: [ s(t) = \sqrt{[x'(t)]^2 + [y'(t)]^2} ]
- At the time when the baseball reaches home plate (60.5 feet), solve for :
- Substituting into :
- Calculating :
- Converting to mph:
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(e) Time when the baseball hits the ground ( )
- Solve for . Using the quadratic formula:
- The two solutions are:
- Since is positive, this is when the ball hits the ground.
Additional Questions
Would you like further details on any part of the solution? Here are some related questions to extend understanding:
- What would change in the problem if air resistance were considered?
- How would different initial velocities affect the trajectory of the baseball?
- Can we model other sports scenarios using similar parametric equations?
- How would we determine the angle at which the baseball was thrown?
- How does this problem relate to projectile motion concepts in physics?
Tip:
When solving parametric equations, always analyze both components (horizontal and vertical) independently before combining them to find the total speed or time of flight.
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Math Problem Analysis
Mathematical Concepts
Calculus
Parametric Equations
Projectile Motion
Velocity and Speed Calculation
Quadratic Equations
Formulas
Horizontal velocity: x'(t) = dx/dt
Vertical velocity: y'(t) = dy/dt
Speed formula: s(t) = √((x'(t))^2 + (y'(t))^2)
Quadratic formula for time when y(t) = 0: t = (-b ± √(b² - 4ac)) / (2a)
Theorems
Pythagorean Theorem (for calculating speed from velocity components)
Derivative of a function (for velocity)
Suitable Grade Level
Grades 11-12 or early college
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