Math Problem Statement
A circus performer stands on a platform and throws an apple from a height of 33.0 m above the ground with an initial velocity v0 as shown in the figure below. A second, blindfolded performer must catch the apple. If v0 = 15.0 m/s, how far from the end of the platform should the second performer stand? (Assume π = 30.0Β°.)
Solution
We are dealing with a projectile motion problem where a circus performer throws an apple with an initial velocity of at an angle from a platform at a height . Our goal is to determine how far the second performer should stand from the end of the platform to catch the apple.
Step 1: Split the initial velocity into components
We first break down the initial velocity into its horizontal () and vertical () components using trigonometry:
Given and :
Step 2: Time of flight
Now, we calculate the total time the apple is in the air. The vertical motion follows this equation:
where (since the apple falls 33 meters below the platform), , and is the acceleration due to gravity.
We solve the quadratic equation for . The equation becomes:
Simplifying:
Rearranging it into a standard quadratic form:
We solve this quadratic equation for .The time of flight is approximately .
Step 3: Horizontal distance
Now that we know how long the apple is in the air, we can calculate the horizontal distance it travels. The horizontal velocity component remains constant because there is no horizontal acceleration.
The horizontal distance is given by:
Substituting and :The second performer should stand approximately from the end of the platform to catch the apple.
Would you like any further details or clarifications?
Here are five related questions you might find useful:
- What happens if the initial velocity of the apple increases?
- How does changing the launch angle affect the horizontal distance?
- What if the platform height is different, how would that impact the outcome?
- How would air resistance alter the calculation?
- Can the apple still reach the performer if they stand closer than the calculated distance?
Tip: Always break down projectile motion into horizontal and vertical components for easier analysis.
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Math Problem Analysis
Mathematical Concepts
Projectile Motion
Trigonometry
Quadratic Equations
Kinematics
Formulas
v_{0x} = v_0 \cos \theta
v_{0y} = v_0 \sin \theta
y = v_{0y} t - \frac{1}{2} g t^2
d = v_{0x} \times t
Quadratic equation: ax^2 + bx + c = 0
Theorems
Kinematic Equations of Motion
Quadratic Formula
Suitable Grade Level
Grades 10-12
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