The expression you provided is:

\[
\cosh(x) \cdot (-\sinh(x)) = -\cosh(x) \sinh(x)
\]

Using the identity for hyperbolic functions:
\[
\frac{d}{dx}(\cosh(x)) = \sinh(x) \quad \text{and} \quad \frac{d}{dx}(\sinh(x)) = \cosh(x),
\]
this expression is simply the product of the hyperbolic cosine and the hyperbolic sine, with a negative sign.

However, there is no immediate simplification without more context, but this product frequently appears in calculus or differential equations when dealing with hyperbolic functions.

Would you like me to explore this further with specific applications or interpretations?

### Relative questions:
1. What is the relationship between hyperbolic functions and exponential functions?
2. How would the expression change if you took the derivative or integral of it?
3. Can this expression represent any physical phenomena in physics or engineering?
4. What is the significance of hyperbolic functions in solving differential equations?
5. How does this compare to the trigonometric sine and cosine functions?

### Tip:
Hyperbolic functions like \(\sinh(x)\) and \(\cosh(x)\) are closely related to exponential functions and play a major role in describing certain types of curves, such as catenaries.

Explore the detailed analysis of the expression cosh(x) * -sinh(x), commonly encountered in calculus and differential equations. Learn about hyperbolic functions, their relationship to derivatives, and their application in solving real-world problems. Suitable for students in Grades 11-12 and college-level calculus.

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