Math Problem Statement
Solution
Let's go through the questions one by one:
Question 4:
A variable is distributed randomly between the values 0 and 4, with the probability density function (PDF) given by:
To find the value of , we must use the fact that the total probability for a PDF is 1, meaning:
Substituting the given PDF:
This will give us the value of .
Question 5:
In four tosses of a coin, let be the number of heads. You are asked to:
- Tabulate the 16 possible outcomes and the corresponding values of .
- Find the probability distribution of , the expected value, and the variance.
Here, follows a binomial distribution with parameters:
- (number of tosses),
- (probability of getting heads in each toss).
We can calculate the probabilities for each value of using the binomial formula:
After determining the distribution, we can compute the expected value and variance:
- Expected value ,
- Variance .
Question 6:
is the number scored in a throw of a fair die. The task involves applying Chebyshev's inequality and finding the actual probability.
Chebyshev's inequality gives the probability that deviates from its mean by more than 2.5:
For a fair die, takes values from 1 to 6, so the mean is:
We'll also find the actual probability using the distribution of .
Would you like me to solve one of these in more detail? Here are 5 related questions to deepen your understanding:
- How do you calculate the variance of a continuous random variable using a PDF?
- What is the interpretation of Chebyshev's inequality in practical terms?
- How does binomial distribution relate to the probability of heads in multiple coin tosses?
- What are the steps to compute the actual probability in question 6?
- How would the expected value change if the coin in question 5 was biased?
Tip: Always verify the normalization condition when dealing with probability density functions (i.e., the total probability should integrate to 1).
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Math Problem Analysis
Mathematical Concepts
Probability Density Function
Binomial Distribution
Chebyshev's Inequality
Expected Value
Variance
Formulas
f(x) = kx^2(4 - x^2)
P(X = k) = (n choose k) * p^k * (1 - p)^(n-k)
Chebyshev's Inequality: P(|X - μ| > kσ) ≤ 1/k^2
Theorems
Chebyshev's Inequality
Binomial Distribution Theorem
Suitable Grade Level
University Level
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