The central angle of sector G is 36°. What is the probability that the spinner lands on G?

To find the probability that the spinner lands on sector G, we can use the ratio of the angle of sector G to the total angle of the circle, which is \(360^\circ\).

Given:
- The angle of sector G: \(36^\circ\)
- Total angle of the circle: \(360^\circ\)

The probability \(P\) that the spinner lands on sector G is calculated as follows:

\[
P = \frac{\text{Angle of sector G}}{\text{Total angle of the circle}} = \frac{36^\circ}{360^\circ}
\]

Simplifying the fraction:

\[
P = \frac{36}{360} = \frac{1}{10} = 0.1
\]

So, the probability that the spinner lands on sector G is \(0.1\) or \(10\%\).

Would you like further details or have any questions?

Here are some related questions you might find interesting:

1. How would the probability change if the angle of sector G were doubled?
2. If the spinner is spun 100 times, how many times would you expect it to land on G?
3. What is the probability of the spinner landing on a sector with an angle of \(45^\circ\)?
4. How would you calculate the probability if the circle were divided into equal sectors?
5. What is the relationship between the central angle and the area of a sector?

**Tip:** Remember that the sum of all central angles in a circle always equals \(360^\circ\). This can be useful when calculating probabilities involving circular sectors!

Discover how to calculate the probability of a spinner landing on sector G with a 36° central angle. This problem covers key geometric and probability concepts, ideal for Grades 6-8. Understand how to apply the formula for sector angles to find probabilities in circular spinners.

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