Math Problem Statement

Out of six computer chips, two are defective. If two chips are randomly chosen for testing (without replacement), compute the probability that both of them are defective. List all the outcomes in the sample space.

Solution

To solve this problem, we will first compute the total number of possible outcomes, then list all outcomes in the sample space, and finally compute the probability that both chosen chips are defective.

Step 1: Total Possible Outcomes

We are selecting two chips out of six, without replacement. The total number of possible outcomes can be found using the combination formula:

Total outcomes=(62)=6!2!(62)!=6×52×1=15\text{Total outcomes} = \binom{6}{2} = \frac{6!}{2!(6-2)!} = \frac{6 \times 5}{2 \times 1} = 15

So, there are 15 possible pairs of chips that can be selected.

Step 2: Defining the Sample Space

We can represent the chips as:

  • D1D_1 and D2D_2 for the two defective chips, and
  • G1,G2,G3,G4G_1, G_2, G_3, G_4 for the four good chips.

Now, we list all possible pairs of chips that can be selected. These are:

  1. (D1,D2)(D_1, D_2)
  2. (D1,G1)(D_1, G_1)
  3. (D1,G2)(D_1, G_2)
  4. (D1,G3)(D_1, G_3)
  5. (D1,G4)(D_1, G_4)
  6. (D2,G1)(D_2, G_1)
  7. (D2,G2)(D_2, G_2)
  8. (D2,G3)(D_2, G_3)
  9. (D2,G4)(D_2, G_4)
  10. (G1,G2)(G_1, G_2)
  11. (G1,G3)(G_1, G_3)
  12. (G1,G4)(G_1, G_4)
  13. (G2,G3)(G_2, G_3)
  14. (G2,G4)(G_2, G_4)
  15. (G3,G4)(G_3, G_4)

This is the complete sample space of all possible outcomes.

Step 3: Finding the Probability that Both Chosen Chips are Defective

There is only 1 outcome in which both chips are defective, which is (D1,D2)(D_1, D_2).

Thus, the probability that both selected chips are defective is:

P(both defective)=Number of favorable outcomesTotal number of outcomes=115P(\text{both defective}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{1}{15}

Final Answer:

The probability that both chips chosen are defective is 115\frac{1}{15}.

Would you like further details or have any questions?

Related Questions:

  1. What is the probability that neither of the chosen chips is defective?
  2. What is the probability that at least one of the chosen chips is defective?
  3. How does the probability change if three chips are chosen instead of two?
  4. What is the probability of selecting one defective and one good chip?
  5. How would the solution change if the chips were chosen with replacement?

Tip:

When solving problems involving combinations, it's useful to first define the total sample space clearly to make counting the favorable outcomes easier.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Probability
Combinatorics

Formulas

Combination formula: C(n, k) = n! / [k!(n-k)!]
Probability formula: P(A) = Favorable Outcomes / Total Outcomes

Theorems

Combination Theorem
Basic Probability Theorem

Suitable Grade Level

Grades 9-12