Math Problem Statement
Solution
The problem asks us to find the probability that a group of 13 people selected from 4 freshmen, 3 sophomores, 6 juniors, and 5 seniors has at least 2 sophomores.
Total number of students:
- Freshmen: 4
- Sophomores: 3
- Juniors: 6
- Seniors: 5
Total students =
Step 1: Total possible selections
We are choosing 13 people from a pool of 18, so the total number of ways to choose 13 students from 18 is:
Step 2: Find complementary probability (no sophomores or only 1 sophomore)
To find the probability of having at least 2 sophomores, we can first find the complementary probability (probability of having 0 or 1 sophomore) and subtract it from 1.
Case 1: No sophomores
If no sophomores are selected, we are choosing all 13 students from the 15 non-sophomores (4 freshmen + 6 juniors + 5 seniors), so the number of ways to do this is:
Case 2: One sophomore
If exactly one sophomore is selected, we first choose 1 sophomore from the 3 available sophomores and then choose the remaining 12 students from the 15 non-sophomores. The number of ways to do this is:
Step 3: Total number of unfavorable selections (0 or 1 sophomore)
The total number of unfavorable selections is the sum of the two cases:
Step 4: Probability of at least 2 sophomores
Now, the probability of having at least 2 sophomores is:
Let me calculate this.The probability that the group of 13 people has at least 2 sophomores is approximately 0.8284 (rounded to four decimal places).
Would you like further details or have any questions?
Here are 5 related questions to explore:
- How would the probability change if the committee required 14 people instead of 13?
- What is the probability of selecting exactly 3 sophomores for the same group size of 13?
- How would you calculate the probability if juniors were the focus instead of sophomores?
- What is the probability of selecting at least 1 sophomore if the group size were reduced to 10?
- How would the total number of possible groups change if only juniors and seniors were considered?
Tip: When calculating complementary probabilities, it's often easier to solve for the opposite event and subtract it from 1.
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Math Problem Analysis
Mathematical Concepts
Probability
Combinatorics
Formulas
Combination formula: C(n, r) = n! / (r! * (n - r)!)
Complementary probability: P(at least event) = 1 - P(not event)
Theorems
Basic Probability Theorems
Complement Rule
Suitable Grade Level
Grades 9-12
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