To find the probability that the 5 oldest people are selected from a group of 6 people when 5 people are randomly chosen, we can break down the problem as follows:

1. Total number of ways to select 5 people from a group of 6:
   The total number of ways to select 5 people out of 6 is given by the combination formula: $\binom{6}{5} = \frac{6!}{5!(6-5)!} = \frac{6!}{5!1!} = 6$ So, there are 6 possible groups of 5 people that can be selected from the group of 6.

2. Favorable outcomes:
   There is exactly 1 favorable outcome, which is selecting the 5 oldest people from the group. This is just one specific combination out of the 6 possible selections.

3. Probability calculation:
   The probability is the ratio of favorable outcomes to total outcomes, which is: $P(\text{5 oldest}) = \frac{1}{6}$

Thus, the probability that the 5 oldest people are selected is $\frac{1}{6}$.

Would you like further clarification on any of the steps?

Here are 5 related questions for further exploration:

1. What is the probability of selecting exactly 4 of the 5 oldest people from the group?
2. How does the probability change if we randomly select 4 people instead of 5?
3. What is the total number of ways to arrange 5 people out of 6?
4. How can the combination formula be applied to larger groups?
5. What if the selection is ordered? How does that affect the outcome?

Tip: When dealing with probabilities, always check whether the selection process considers order (permutations) or is independent of order (combinations).