The image contains a probability problem based on a lottery and a binomial calculation. From what I can make out:

• The lottery has a pool of 36 possible numbers, and the player selects 6 numbers.
• The problem asks about the probability of selecting 2 specific correct numbers.
• A combination formula is provided, $C = \binom{n}{k}$, to compute the number of combinations.

The formula at the bottom is:

$C = \binom{6}{2} \times \binom{30}{4}$

This refers to selecting 2 correct numbers out of 6 and then selecting 4 incorrect numbers out of the remaining 30. The combination formula $\binom{n}{k}$ computes how many ways you can choose $k$ items from $n$ items without regard to the order.

Would you like me to break down this formula step by step, calculate the result, or explain any specific part further?

Here are 5 follow-up questions:

1. What does the combination formula $\binom{n}{k}$ signify in this context?
2. Why do we multiply the combinations in this calculation?
3. What other probability scenarios can this approach apply to?
4. How do the total possible outcomes affect the final probability?
5. What role does the number 30 play in the selection process here?

Tip: Always check if you’re calculating a combination (order doesn’t matter) or permutation (order matters) based on the problem’s context.