A fair six-sided number cube (die) is rolled.  Find the probability of getting less than a 6.

A fair six-sided die has numbers 1, 2, 3, 4, 5, and 6 on it. The probability of an event is calculated as:

\[
\text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}
\]

In this case, you want to find the probability of rolling a number less than 6. The favorable outcomes are 1, 2, 3, 4, and 5, which are 5 possible outcomes.

The total number of possible outcomes is 6 (since the die has 6 faces).

Thus, the probability of getting a number less than 6 is:

\[
P(\text{less than 6}) = \frac{5}{6}
\]

This simplifies to approximately:

\[
P(\text{less than 6}) = 0.8333
\]

So, the probability is \( \frac{5}{6} \) or approximately 83.33%.

Would you like further details or have any questions?

Here are 5 related questions:
1. What is the probability of rolling a number greater than 4 on a six-sided die?
2. If you roll two six-sided dice, what is the probability of both showing a number less than 6?
3. How does the probability change if we roll an eight-sided die instead?
4. What is the probability of rolling an even number on a six-sided die?
5. What is the probability of rolling a number less than or equal to 3 on a six-sided die?

**Tip:** When solving probability problems, always check how many outcomes meet the condition you’re interested in and compare that to the total number of possible outcomes.

A fair six-sided number cube (die) is rolled. Find the probability of getting less than a 6.

Learn how to calculate the probability of rolling a number less than 6 on a fair six-sided die. This problem covers basic probability concepts, using the formula of favorable outcomes over total outcomes. Suitable for students in Grades 5-7.

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