A fair six-sided die has numbers 1, 2, 3, 4, 5, and 6 on it. The probability of an event is calculated as:

$\text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}$

In this case, you want to find the probability of rolling a number less than 6. The favorable outcomes are 1, 2, 3, 4, and 5, which are 5 possible outcomes.

The total number of possible outcomes is 6 (since the die has 6 faces).

Thus, the probability of getting a number less than 6 is:

$P(\text{less than 6}) = \frac{5}{6}$

This simplifies to approximately:

$P(\text{less than 6}) = 0.8333$

So, the probability is $\frac{5}{6}$ or approximately 83.33%.

Would you like further details or have any questions?

Here are 5 related questions:

1. What is the probability of rolling a number greater than 4 on a six-sided die?
2. If you roll two six-sided dice, what is the probability of both showing a number less than 6?
3. How does the probability change if we roll an eight-sided die instead?
4. What is the probability of rolling an even number on a six-sided die?
5. What is the probability of rolling a number less than or equal to 3 on a six-sided die?

Tip: When solving probability problems, always check how many outcomes meet the condition you’re interested in and compare that to the total number of possible outcomes.