Math Problem Statement

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There is a 43% chance that Riya walks to work. Given that Riya walks to work, she meets her friend Jasmine 30% of the time, and if she does not walk to work, she meets Jasmine 25% of the time. Find the probability that Riya walks to work on any particular day, given that she met Jasmine.

Solution

Let's solve Question 16 from the uploaded image:

Question 16:

There is a 43% chance that Riya walks to work. Given that Riya walks to work, she meets her friend Jasmine 30% of the time, and if she does not walk to work, she meets Jasmine 25% of the time. Find the probability that Riya walks to work on any particular day.

Solution

Let's denote the following events:

  • WW: Riya walks to work.
  • MM: Riya meets Jasmine.

From the problem statement, we know:

  • P(W)=0.43P(W) = 0.43, the probability that Riya walks to work.
  • P(MW)=0.30P(M | W) = 0.30, the probability that Riya meets Jasmine given that she walks to work.
  • P(MWc)=0.25P(M | W^c) = 0.25, the probability that Riya meets Jasmine given that she does not walk to work.

We need to find the probability that Riya walks to work, P(W)P(W), which is already given as 43% or 0.430.43.

However, if the question is asking for the probability that Riya walks to work on a particular day given that she met Jasmine, we would apply Bayes' theorem.

Finding P(WM)P(W | M)

According to Bayes' theorem: P(WM)=P(MW)P(W)P(M)P(W | M) = \frac{P(M | W) \cdot P(W)}{P(M)}

Step 1: Calculate P(M)P(M)

Using the law of total probability: P(M)=P(MW)P(W)+P(MWc)P(Wc)P(M) = P(M | W) \cdot P(W) + P(M | W^c) \cdot P(W^c) where P(Wc)=1P(W)=10.43=0.57P(W^c) = 1 - P(W) = 1 - 0.43 = 0.57.

Substitute the known values: P(M)=(0.30)(0.43)+(0.25)(0.57)P(M) = (0.30)(0.43) + (0.25)(0.57) Calculate each term:

  1. (0.30)(0.43)=0.129(0.30)(0.43) = 0.129
  2. (0.25)(0.57)=0.1425(0.25)(0.57) = 0.1425

So, P(M)=0.129+0.1425=0.2715P(M) = 0.129 + 0.1425 = 0.2715

Step 2: Substitute into Bayes' formula

Now we can find P(WM)P(W | M): P(WM)=(0.30)(0.43)0.2715P(W | M) = \frac{(0.30)(0.43)}{0.2715} P(WM)=0.1290.27150.4751P(W | M) = \frac{0.129}{0.2715} \approx 0.4751

Final Answer

The probability that Riya walked to work on a particular day, given that she met Jasmine, is approximately 0.4751 or 47.51%.


Would you like a breakdown of any step or more details?

Related Questions

  1. How would the probability change if the chance of meeting Jasmine without walking was increased?
  2. What would P(WMc)P(W | M^c) be, where McM^c is the event that Riya does not meet Jasmine?
  3. How does Bayes' theorem apply in scenarios with conditional probabilities?
  4. If P(W)P(W) changed to 50%, how would that affect P(WM)P(W | M)?
  5. How can we apply the law of total probability in real-life situations?

Tip

When dealing with conditional probability questions, always check if Bayes' theorem is applicable by identifying "given" conditions.

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Math Problem Analysis

Mathematical Concepts

Conditional Probability
Bayes' Theorem
Law of Total Probability

Formulas

Bayes' Theorem: P(A|B) = (P(B|A) * P(A)) / P(B)
Law of Total Probability: P(B) = P(B|A) * P(A) + P(B|A') * P(A')

Theorems

Bayes' Theorem

Suitable Grade Level

Grades 10-12