https://file.aiquickdraw.com/mathbot/file/1729060085792t08ym6rt.jpg

Let's solve the problem step by step:

### Total number of jellybeans:
- 14 black
- 9 red
- 13 yellow
- 5 green

Adding them all together:
\[
14 + 9 + 13 + 5 = 41
\]
So, there are 41 jellybeans in total.

### Probability that it is red or yellow:
- The number of red jellybeans: 9
- The number of yellow jellybeans: 13

Thus, the total number of favorable outcomes (red or yellow) is:
\[
9 + 13 = 22
\]

#### Probability as a reduced fraction:
\[
\frac{\text{Favorable outcomes}}{\text{Total outcomes}} = \frac{22}{41}
\]
Since 22 and 41 have no common factors, the fraction is already in its simplest form.

#### Probability as a percentage:
To find the percentage, divide 22 by 41 and multiply by 100:
\[
\frac{22}{41} \times 100 \approx 53.66\%
\]
Rounded to the nearest whole number, the probability is approximately **54%**.

### Final Answers:
1. Probability as a reduced fraction: \(\frac{22}{41}\)
2. Probability as a percentage (rounded to nearest 1%): **54%**

Let me know if you need further details!

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Here are 5 related questions to expand your understanding:
1. What would the probability be if you only considered the green jellybeans?
2. How would the probability change if the number of black jellybeans was doubled?
3. What is the probability of selecting a black or green jellybean?
4. How would you calculate the probability if the question asked for *not* red or yellow jellybeans?
5. How do you convert a fraction to a percentage in general?

**Tip:** Always check if a fraction can be simplified by finding the greatest common divisor (GCD) of the numerator and denominator.

A jar on your desk contains 14 black, 9 red, 13 yellow, and 5 green jellybeans. You pick a jellybean without looking. Find the probability that it is red or yellow.

Learn how to find the probability of picking a red or yellow jellybean from a jar containing black, red, yellow, and green jellybeans. This problem covers basic probability, fractions, and percentage calculations. Suitable for students in Grades 6-8.

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