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To solve this problem, let's calculate the probability that the jelly bean picked is **not green**.

### Step 1: Calculate the Total Number of Jelly Beans
From the given information:
- Black jelly beans = 12
- Red jelly beans = 8
- Yellow jelly beans = 10
- Green jelly beans = 5

The total number of jelly beans is:
\[
12 + 8 + 10 + 5 = 35
\]

### Step 2: Calculate the Number of Jelly Beans That Are Not Green
Since there are 5 green jelly beans, the number of jelly beans that are **not green** is:
\[
35 - 5 = 30
\]

### Step 3: Set Up the Probability
The probability that a jelly bean picked is not green is the ratio of non-green jelly beans to the total number of jelly beans:
\[
\frac{\text{Number of Non-Green Jelly Beans}}{\text{Total Number of Jelly Beans}} = \frac{30}{35}
\]

### Answer (in Unsimplified Fraction Form)
The probability that the jelly bean picked is not green is:
\[
\frac{30}{35}
\]

Would you like more details on the calculation? 

Here are some related questions to explore:
1. What is the probability of picking a green jelly bean?
2. If two jelly beans are picked, what is the probability both are black?
3. How would the probability change if 3 additional green jelly beans are added?
4. What is the probability of picking either a red or a yellow jelly bean?
5. How many ways can two jelly beans of the same color be chosen?

**Tip:** Always check whether simplifying fractions is required; some problems specify an unsimplified fraction, as in this case.

A jar on your desk contains twelve black, eight red, ten yellow, and five green jelly beans. You pick a jelly bean without looking. What is the probability that the jelly bean is not green? Enter your answer as an unsimplified fraction.

Learn how to calculate the probability of picking a non-green jelly bean from a jar containing black, red, yellow, and green jelly beans. This example covers probability concepts and is suitable for students in Grades 6-8.

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