Math Problem Statement
Kotak I berisi 5 bola putih dan 4 bola kuning. Kotak II berisi 3 bola putih dan 6 bola kuning. Dari masing-masing kotak dipilih bola secara acak. Peluang terambilnya bola berlainan warna adalah
Solution
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Math Problem Analysis
Mathematical Concepts
Probability
Combinatorics
Formulas
P(putih dari Kotak I) = 5/(5+4)
P(kuning dari Kotak II) = 6/(3+6)
P(kuning dari Kotak I) = 4/(5+4)
P(putih dari Kotak II) = 3/(3+6)
Total probability = P(putih Kotak I dan kuning Kotak II) + P(kuning Kotak I dan putih Kotak II)
Theorems
Law of Total Probability
Suitable Grade Level
Grades 9-11
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